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2007
Mon
23
Apr
Miss Loi avatar

Trigonometry – My Grandmother Also Can Do This!

(2)
Tuition given in the topic of E-Maths Tuition Questions from the desk of Miss Loi at 5:39 pm (Singapore time)

Today’s question looks sooo simple. Just punch those keys on your state-of-the-art Casio scientific calculator and you will get it right … except that this is a Paper 1 question and your favourite Casio calculator should not be there!

So how now? Go ask your Grandma (Ah SOH) with the big foot (TOA CAH) for help lah!

Diagram for this question In the diagram, a ladder BC is leaning against the wall AD. Given that, sin x = 5/13. Find the cosine of angle DCB.

頑張って!!!

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2 Comments

  1. Nick's Avatar
    Nick commented in tuition class


    2007
    May
    6
    Sun
    6:25pm
     
    1

    sin x = 5/13 => sin ABC = 5/13 => cos BCA = 5/13 => cos DCB = -5/13.

  2. Miss Loi's Avatar
    Miss Loi Friend Miss Loi on Facebook @MissLoi commented in tuition class


    2007
    May
    7
    Mon
    12:55pm
     
    2

    Great stuff Nick!

    The purpose of this question is to remind students that the standard trigo ratios (i.e. TOA CAH SOH -> Tan: Opp/Adj; Cos: Adj/Hypo; Sin: Opp/Hypo) applies only to an acute angle.

    In order to solve for angle DCB which is an obtuse angle in the question, students need to remember a further set of equations i.e:

    sin θ = sin (180o - θ)
    cos θ = -cos (180o - θ)
    tan θ = -tan (180o - θ)

    Hence exam questions usually require multiple steps like these. If everyday just simply TOA CAH SOH TOA CAH SOH, the examination board can close shop liao!

    So remember this well!

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