2009
Mon
16
Nov
Mr Loi avatar

GCE A-Level 2009 H1 Maths 8863 & H2 Maths 9740 Paper 2 Suggested Answers & Solutions

(10)

Hello everyone, it’s me again.

I’ve been busy over the weekend with my classes and it seems that I’ve been missing out a bit of action on the H2 Maths Paper 2. Anyway I’ve found some time today to work out the following H1 Maths 8863 Paper 1 and H2 Maths 9740 Paper 2 (yes I know I’m bit WOLS on this one :P) just to complete my set of A Level Maths suggested solutions for this year (2009):

A-Level 2009 October/November H1 Maths 8863 Paper 1 Solutions A-Level 2009 October/November H2 Maths 9740 Paper 2 Solutions
2009 ‘A’ Level October/November H1 Maths 8863 Paper 1 (left) & H2 Maths 9740 Paper 2 (right) Suggested Solutions - click to download

As usual, please check if they tally with your solutions and inform me (gently) in the comments below if you discover any mistake or disagree with any of the answers described within. This is especially so for the H1 Maths paper which there has been an absence of any discussion on it, as far as I know.

Now that the A-Level maths papers are over, I sincerely hope that all of you have managed to handle this year’s maths papers with confidence. I also hope that my shortlist of probable pure maths topics (a number of which indeed came out) has benefitted some of you in your last-minute revision.

Anyway, it’s time now to focus on the rest of your papers and try not to be caught up with all the speculative talk on moderation and worry about what grades you’re going to get (after all, no one really knows). Instead be glad that you have done your best and strive to work harder for your remaining papers!

Once again, all the best!

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Comments

10 Comments

  1. 1


    2009
    Mon
    16
    Nov
    3:47AM
    hx says,

    Thanks for the h1 maths solutions! even though i cant really remember my solutions now, i think i should be able to get an A. :D

  2. 2


    2009
    Tue
    17
    Nov
    10:47AM
    anon991 says,

    The H2 math paper, the question on hypothesis testing is whether the mean deviates from the assume value. Then shouldnt the variance be divided by 9 as well since it should be mean???

  3. 3


    2009
    Tue
    17
    Nov
    2:01PM
    Mr Loi avatar Mr Loi says,

    hx: Congrats, for I think that this H1 paper can be quite challenging for some Time to stay focussed to get your As for the rest of your subjects :D

    anon991: Are you referring to the t-test in Q10(ii)? If so, then I believe it has already been divided
    i.e. T ={overline{X}-mu}/{s/sqrt{n}}, where s is the unbiased estimate of the population variance of X.

  4. 4


    2009
    Thu
    19
    Nov
    4:21PM
    Jocelyn says,

    Hey, for H2 math p2, q6 on the world record running times. i think you may have misread the question. the values given in the table are seconds above 3mins and 30seconds. can you kindly clarify there?

    Thanks!

  5. 5


    2009
    Thu
    19
    Nov
    4:55PM
    ken says,

    hey for 11iv , if they state P(R=0 or 1) = 0.2
    isnt it P(R=0) = 0.2 , P(R=1) = 0.2
    so we can equate both tgt and use binomial formula to solve for p ?

  6. 6


    2009
    Thu
    19
    Nov
    4:56PM
    ken says,

    sry i mean 11(V)

  7. 7


    2009
    Thu
    19
    Nov
    4:59PM
    Jocelyn says,

    no i think they meant

    P(R=0)+P(R=1) = 0.2

  8. 8


    2009
    Thu
    19
    Nov
    5:46PM
    Nash says,

    @jocelyn The world record question the time taken will be 11.4s above 3min 30sec

  9. 9


    2009
    Fri
    20
    Nov
    11:56PM
    Mr Loi avatar Mr Loi says,

    Thanks for pointing it out Jocelyn. I think you are referring to the second para of answer of Q6(ii) - I actually realized it’s t above 3 min 30 sec midway through Q6 but forgot to amend 6(ii) *sigh*

    Anyway I’ve amended Q6(ii) to highlight that

    a non-linear model (with a negative exponential function) may be more appropriate than a linear model since it is unlikely that the world record will decrease linearly with time, given that it’s likely to be increasingly difficult to break it as we approach the limits of our human abilities.”

    Of course the above may not be true if we are talking about Usain Bolt but let’s not go there … :P

    ken: P(R = 0 or 1) = 0.2 actually means
    = P(R = 0) ∪ P(R = 1)
    = P(R = 0) + P(R = 1) since P(R = 0) ∩ P(R = 1) = 0 as 0 and 1 red car cannot be observed at the same time.

    Think you got a little mixed up about independent trials in a binomial distribution. Though each trial is independent of one another, you can’t assume that P(R = 0) = P(R = 1) = 0.2 since this is not a given in the question.

  10. 10


    2009
    Sat
    5
    Dec
    12:35AM
    Kenneth says,

    I’m from Millenia Institute and my 3 year education is going to own your ass RJC noob cakes!

    We all thought the math paper this year is super easy siah confirm pwn your lan la. See our school get top this year

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