2008
Thu
15
May
Miss Loi avatar

Guess Where I Am? :)

(2)

Hi! :)



2008
Wed
14
May
Miss Loi avatar

One Night In Bangkok But No Trace Of Pingsters

(2)

Official Glass of Platinum Food Center

*Sits down with a lone glass of oren juice at the top of Platinum Fashion Mall and looks around*

Don’t think there’s gonna be any Ping.sg gathering here today :P.

Platinum Mall Shopping Erawan Shrine
Healthland Spa Pink Taxis
Suay Siam Shoes



2008
Sun
11
May
Miss Loi avatar

When Rabbits Munch On Fresh Green Grass, They Cannot See The Storm Coming From The Horizon

(8)
Platinum Fashion Mall
Platinum Fashion Mall - One of the stops on
Miss Loi’s pilgrimage trail.

Like starving rabbits freed from the shackles of their little cages, they bounded past the Temple Gates towards the vast open meadows of freedom beyond, where they hope to pick up where they left off a month ago: be it restarting a saved computer game, salvaging a once-decent figure ruined by junk food, or finally mustering enough courage to ask that chick out for a movie.

As they bask in the glorious sunshine that envelops the plains, few, however, notice the cluster of brooding storm clouds gathering on the horizon.

But notice them Miss Loi (with her geeky 450o glasses supernatural eyesight) did.

And as thoughts of The Cause is never far from her mind, even as the Temple Gates creak to a close in preparation for the holy dates (13-23 May) of her annual shopping pilgrimage, the High Priestess has decreed, on this Day of Love, the following schedule for the imminent salvation of the growing ranks of LMBFH Syndrome sufferers:

Miss Loi’s June Holiday Intension Revision Jφss Sticks Sessions (27 May-22 June 2008)

Lesson Times:
Mondays to Thursdays 3.00-5.00pm (E-Maths)
5.00-7.00pm (A-Maths)

Fridays 3.00-5.00pm (E-Maths)
5.00-7.00pm (A-Maths)
7.00-9.00pm (A-Maths)

Saturdays 10.30am-12.30pm - Full (blocked for existing students)
1.00-3.00pm (Subject TBC - pending enquiries)
3.00-5.00pm (Subject TBC - pending enquiries)
5.00-7.00pm - Full (blocked for existing students)

Sundays 1.00-3.00pm (Subject TBC - pending enquiries)
3.00-5.00pm (Subject TBC- pending enquiries)
5.00-7.00pm - Full (blocked for existing students)

Venue: Miss Loi’s Temple
Class Size: Exclusive to 4-6 students/class
Duration/Session: 2 hours
Included: Drinks and light snacks
Miss Loi’s fabled Exam Papers
School uniform is optional (but still must wear something okay!)

As per last year, these intensive tuition sessions are designed to cover the entire O-Level Mathematics syllabus within this June holidays. To ensure that every single participant will receive Miss Loi’s maximum tender loving care, each session is limited to a maximum of six students.

Lastly, history has shown that a major schedule announcement like this is usually followed by a chaotic tremendous surge in spiritual fervour.

As such, Miss Loi implores you to contact her at your earliest convenience to confirm your early salvation, for it’ll be too late when you see pot-bellied beer-drinking security guards deployed for crowd control at the Temple Gates to ensure that no one (not even a limping terrorist) sneaks in!

Gone Shopping!

Miss Loi will be on her overseas pilgrimage trail from 13-23 May.

Please email missloi [at] exampaper [dot] com [dot] sg during this period as her mobile phone might not be reachable at times, and she will try to get back to you as soon as she can find the next internet access point.



2008
Tue
6
May
Sergeant Loi avatar

Sergeant Loi’s Mid-Year Boot Camp 2008 - Finding Your Roots With Remainder & Factor Theorems

(8)
Sergeant Loi's Helmet
This heavy thing is causing permanent damage
to her previously-rebonded hair

One more time …

*Puts on helmet*

*SHOWS STERN & MEAN & TIRED FACE*

*Sounds bugle* EVERYBODY FALL IN!

Most of you would’ve started your Mid-Year Exams by now - a series of no-holds-barred trials to determine once and for all if indeed a wind tunnel exists between your ears to test your understanding of topics taught in Semester 1.

For some, this could also be a time for your ‘chers to avenge all the tortures you’ve subjected them to throughout the term. As such, the Mids always tend to be a little on the sadistic side, and strewn with devious tricks around every turn and corner.

That’s why Miss Sergeant Loi (whose Teresa Teng voice is now hoarse from all the shouting) is here - to hopefully help save you a mark or two, to give you that little bit of edge from being pwned by your ‘chers.

So let’s do this one more time (to complete the chapter on Polynomials) … for now

Remainder & Factor Theorems

A. REMAINDER THEOREM

If f(x) is divided by (x - a) ⇒ the remainder is f(a)

e.g. Find the remainder when 4x3 - 5x + 1 is divided by:
i. x-2, ii. x+3, iii. 2x-1

Ans: Let f(x) = 4x3 - 5x + 1. Remainder, R =

  1. f(2) = 4(2)3-5(2)+1 = 23
  2. f(-3) = 4(-3)3-5(-3)+1 = -92
    → note it’s divided by x (+) 3 so you’re have to sub in (-)3 instead
  3. f(½) = 4(½)3-5(½)+1 = -1
    → note when divided by (2x-1) → you’ll have to convert it to the form (x-½) first and then sub in the ½

Warning! DON’T waste time doing long division in remainder theorem questions!!!

B. FACTOR THEOREM

If f(x) is divided by (x - a) and the remainder is 0 ⇔ f(a)=0
⇒ (x - a) is a factor of f(x)
⇒ f(x) is exactly divisible by (x - a)

From your Sec Two Expansion & Factorisation chapter:

  1. Expansion → remove brackets
  2. Factorisation → put back brackets ⇒ final answer must always be in brackets!

e.g. Factorise x2 - 5x + 6

Ans via Trial & Error (try getting this under 10 sec :D ):

Choose 2 factors of the constant 6
try: 1 x 6 → 1x + 6x ≠ -5x (reject)
try: 2 x 3 → 2x + 3x ≠ -5x (reject)
try: (-2) x (-3) → -2x + (-3)x = -5x (YAY!)
⇒ cross-check: f(3) = f(2) = 0 (YAY!)
x2 - 5x + 6 = (x - 3)(x - 2)

Warning! When you see the keyword Factorise, final answer must be in (brackets) i.e. don’t try to be funny and write x = 3, 2 → minus marks!

C. SOLUTION OF EQUATIONS

When you spot the keywords Solve and/or = 0 in your exam question, it means you’ll normally have to:

  1. Find the factors of an equation f(x) (usually cubic)
  2. Find the roots of f(x)=0 (i.e. final answer must be in the form: x = a, b … where a, b, … are the roots)

e.g. Solve 3x3 - 10x2 + 9x - 2 = 0

Ans: Let f(x) = 3x3 - 10x2 + 9x - 2.

  1. Find the first factor via trial and error

    Try x=1: f(1) = 3(1)3 - 10(1)2 + 9(1) - 2 = 0 (YAY!)
    ⇒ (x-1) is a factor

  2. Find the remainder expression by either COMPARING COEFFICIENTS:

    Factorization by Comparing Coefficients

    OR LONG DIVISION (if you’re a long division aficionado)

    Factorization by Long Division

    You should get the SAME expression either way - use which ever method you’re more comfortable with (use one method to cross check the other if you’re one of those with lotsa free time left in your exam).

  3. Factorize the remaining quadratic expression 3x2-7x+2 (via quick Trial and Error method described in B above):

    Choose 2 factors of the constant 2
    try: (-2) x (-1) → (3)(-2)x + (-1)x = -7x (YAY!)
    → Note the coefficient of 3 of the x2 term
    ⇒ 3x2 - 7x + 2 = (3x - 1)(x - 2)
    → Note it’s NOT (3x - 2)(x - 1) coz you need to corss-multiply
    ⇒ cross-check: f(⅓) = f(2) = 0 (YAY!)

    ⇒ 3x3 - 10x2 + 9x - 2 = (x-1)(3x-1)(x-2) = 0
    x = 1, 2, ⅓

Warning! When you see the keywords Solve and/or = 0, final answer must be in the form x = a, b … i.e. don’t stop at factorising → minus marks!
Warning! Sometimes the quadratic equation in Step 3 cannot be easily factorised → you’ll have to use the Quadratic Formula to find the two solutions. You’ll normally get the hint when you see terms like ±√ within the question.

SAMPLE PRACTICE QUESTION

The cubic polynomial f(x) is such that the coefficient of x3 is -1 and the roots of the equation f(x) = 0 are 1, 2 and k. Given that f(x) has a remainder of 8 when divided by x-3, find

  1. the value of k,
  2. the remainder when f(x) is divided by x+3

Ans:

Since 1, 2 and k are roots, a(x-1)(x-2)(x-k) = 0
→ straightaway write down in factorized form once roots are known
→ always remember to include the coefficient a for x3 for it may not always be 1!

And since coefficient of x3 = -1
a = -1
⇒ (-1)(x-1)(x-2)(x-k) = 0

Let f(x) = (-1)(x-1)(x-2)(x-k)

  1. Since remainder is 8 when divided by (x-3),
    f(3) = (-1)(3-1)(3-2)(3-k) = 8
    (using Remainder Theorem from A above)
    k = 7
  2. Now using k = 7 above, f(x) = (-1)(x-1)(x-2)(x-7)

    Remainder when divided by x+3:
    → f(-3) = (-1)((-3)-1)((-3)-2)((-3)-7) = 200

*For some reason, students have a habit of expanding the entire expression after they’ve written down everything in factorized form = what a waste of time. Tsk.

As always, get these rules drilled into your head! Spot the pointers and common mistakes in red! Understand the representative sample question! Check out further questions on factor theorem!

Print this out if necessary and remember the above procedures by heart … and do let Miss Loi know which topics and stuffs you would like to see in her next set of Maths Notes ;)

Till then, understand that the ultimate root of your own equation is to prepare youself in mind and in soul for the Great War at year’s end. So don’t be afraid to make all the mistakes you need to make now (as long as you know what mistakes you’re making!).

Good Luck For Your Mids!

P.S. To the reader who longs and yearns to see Miss Loi’s divine face again, a very heartbroken and upset Sergeant Loi was last seen charging out of camp with her Katana sword, vowing to hunt this reader down, and slice him into many pieces and use the Remainder Theorem to turn whatever that remains of him into 人肉叉烧包 (human buns)!


2008
Sun
4
May
Sergeant Loi avatar

Sergeant Loi’s Mid-Year Boot Camp 2008 - Rationalising The Rationale Of Surds

(7)
Surds
Don’t worry.
These aliens are often friendlier than they look.

*Puts on helmet*

*SHOWS STERN & MEAN FACE*

*Sounds bugle* EVERYBODY WAKE UP!

Sergeant Loi is back from her May Day leave - only to find The Temple in a state of 兵慌马乱 as the mid-year exams loom.

To whip everyone back to shape, Sergeant Loi shall complete the trinity (which began with indices, and followed by logarithms) with the concluding drill on surds today!

Despite the scary-looking longish workings, surds are the most straightforward part of the trinity. For most parts, the TWO main things you’ll ever need to know are how to simplify (with a dose of trial-and-error common sense) and rationalise surd expressions.

That’s it! Now let’s go eat some surds for breakfast!

*Cracks whip*

The Rationale of Surds

A. WHAT IS A SURD?

High-class definition:
An irrational root of a real number. *sweats*

Simple O Level definition:
A *square-root of a number that results in endless decimal places when you press your calculator e.g.

  1. √2 is a surd (=1.4142135623 … when you press your calculator)
  2. √9 is NOT a surd (= 3 when you press your calculator - WOW NO DECIMALS!)

*Actually can also be cube-root, nth-root etc. but let’s not go there …

B. THE OPERATIONS OF SURDS

  1. sqrt{a}*sqrt{a} = a
  2. sqrt{a}*sqrt{b} = sqrt{ab}
  3. sqrt{a}/sqrt{b} = sqrt{a/b}
  4. m sqrt{a}+n sqrt{a} = (m+n)sqrt{a}
  5. m sqrt{a}-n sqrt{a} = (m-n)sqrt{a}

*Compare operations B(2) & B(3) to the Rules of Indices (Part C) and you’ll realize they’re like long-lost twins!

e.g. Simplifying surd expressions:

  1. √18 = √(9 × 2) = √9 × √2 = 3√2
    → Using B(2) and a tiny bit of trial and error to get the (9 × 2)
  2. 3√2 + 5√2 = (3 + 5)√2 = 8√2 → Using B(4)
  3. (√5 - √2)2 = (√5 - √2)(√5 - √2)
    = √5√5 - √5√2 - √2√5 + √2√2
    = 5 - √10 - √10 + 2 → Using B(1) + B(2)
    = 7 - 2√10 → Using B(4)
Warning! DON’T ever do this:

√(a+b) ≠ √a + √b → WRONG!
√(a-b) ≠ √a - √b → WRONG!

e.g.
√64 ≠ √32 + √32!
√25 ≠ √12 + √13!

C. CONJUGATE SURDS

(ha + kb)(ha - kb) = h2a - k2b
(Note the MINUS sign on the RHS)

e.g. (√3 + √2)(√3 - √2) = 3 - 2 = 1

Warning! DON’T ever do these:

(√a - √b)2 ≠ (√a2 - √b2) → WRONG!
(√a + √b)(√a - √b) ≠ (√a)2 + (√b)2 → WRONG!

D. RATIONALISING THE DENOMINATORS OF SURDS

Having a surd in the denominator is IMPROPER, UNGLAM, SINFUL & IMMORAL!!!

So we need to rationalise the denominators by multiplying the top and bottom by the same number with respect to the denominator i.e.

  1. If denominator consists of a single term → multiply top & bottom by denominator term e.g.
    1/sqrt{3} = {1/sqrt{3}} * {sqrt{3}/sqrt{3}} = sqrt{3}/3
  2. If denominator consists of 2 terms → multiply top & bottom by conjugate of denominator e.g.
    1/{sqrt{2}-1} = {1/{sqrt{2}-1}} * {{sqrt{2}+1}/{sqrt{2}+1}} = {sqrt{2}+1}/{(sqrt{2}-1)(sqrt{2}+1)}
    {}= {sqrt{2}+1}/{sqrt{2}^2-1^2} = {sqrt{2}+1}/{2-1} = sqrt{2}+1

SAMPLE PRACTICE QUESTIONS

  1. Simplify {4-sqrt{5}}/{2sqrt{5}+3}.

    Ans:

    {{4-sqrt{5}}/{2sqrt{5}+3}} * {{2sqrt{5}-3}/{2sqrt{5}-3}}
    → multiply top & bottom with conjugate surds (C)
    {} = {(4-sqrt{5})(2sqrt{5}-3)}/{(2sqrt{5})^2 - (3)^2}
    {} = {8 sqrt{5} - 12 - 10 + 3 sqrt{5}}/{4(5)-9} = {11 sqrt{5} - 22}/{11} = sqrt{5} - 2

  2. Given that {2/sqrt{2}}({{3sqrt{54}}/4}-{15/sqrt{150}}-{14/sqrt{294}})=k sqrt{3}, find the value of k.

    Ans:

    → Rationalize all the sinful terms with surds in denominator!
    {2/sqrt{2}}*{sqrt{2}/sqrt{2}}({{3sqrt{54}}/4}-{15/sqrt{150}}*{sqrt{150}/sqrt{150}}-{14/sqrt{294}}*{sqrt{294}/sqrt{294}})
    {}=k sqrt{3}
    doubleright {{2 sqrt{2}}/2}({{3sqrt{54}}/4}-{{15 sqrt{150}}/150}-{{14 sqrt{294}}/294})=k sqrt{3}
    → Now simplify the surds using B(2) above and a tiny bit of trial and error
    doubleright sqrt{2}({{3sqrt{9*6}}/4}-{{15 sqrt{25*6}}/150}-{{14 sqrt{49*6}}/294})=k sqrt{3}
    doubleright sqrt{2}({{9sqrt{6}}/4}-{{sqrt{6}}/2}-{{sqrt{6}}/3})=k sqrt{3}
    doubleright sqrt{2}(17/12)sqrt{6}=k sqrt{3}
    → split √6 into √2√3 since we’re going to compare with the √3 term on RHS
    doubleright sqrt{2}(17/12)sqrt{2}sqrt{3}=k sqrt{3}
    doubleright (34/12)sqrt{3} = (17/6)sqrt{3} =k sqrt{3}
    doubleright k = 17/6 via comparing coefficient of √3

As always, get these rules drilled into your head! Spot the pointers and common mistakes in red! Understand the representative sample questions! Check out more surds in action!

Print this out if necessary and remember the above procedures by heart, for if you fail in rationalizing surds in your exams, you’ll need to write a 1000000-word essay to Sergeant Loi explaining the rationale for not punishing you!

*Cracks whip*

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