E-Maths Graphs questions may look intimidating to some students but they are actually quite straightforward and are often restricted to only a few marks in Paper 1 – leaving them with the dubious honour of taking up the most paper space but offering the least marks.

Think of them as marks on a platter, and you don’t really need to be an artist to sketch well.

Nonetheless these are the if-you-got-study-then-you-will-score type of questions, so you *die die* have to get yourself familiarized with the **12 Graphs of Functions** in your text book.

But do bear in mind that their simplicity may make some evil examiners so ashamed of themselves that they have to resort to some lame twists just to squeeze out that extra 1% of your brain juice. As with many of Miss Loi’s questions, always remember the actual exam questions will seldom *look* the same as what is in your textbook, but with an additional step on your part, you’ll find that they are actually the same thing!

- The sketch represents the graph of
`y`=`x`^{n}.Write down a possible value of

`n`. - The point (1, 2) is marked on the diagram below. On the diagram, sketch the graphs of
`y`= (1/`x`) + 1`y`= 2^{x}

P.S. Before any of you A-Level student, or Uni Math Major, or PhD or whatever start screaming “*Walau*! Don’t insult my intel! My grandmother also can do this!”, do note that we are talking about **Secondary School E-Maths** level here.

P.P.S. Miss Loi understands that not everyone is proficient with an image editing software, so should you wish to ‘sketch’ these out in the comments, maybe you can answer the way this student did

## 4 Comments

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1. A possible value of n is -2.

Yes the sketch depicts a classic graph which is one of the

12 Graphs of Functionsin your text book, wherea> 0In this case,

a= 1 andn= -2. Actually to probe further, the graph looks similar forn= -2, -4, -6, ... (all negative even numbers)2i.

from the positive x-axis:

from the negative x-axis:

:

:

The curve on LHS of x-axis cuts x-axis at (-1,0).

The curve has no maximum or minimum value.

and the curve passes through the given point!You did a great job in highlighting the

asymptotesi.e. where the graph approaches zero or infinity.However EMaths students simply need to first recall the shape of (shown in grey in the diagram above), and then understand that the constant (+1) in means that we're

shifting upwardsby one unit (see diagram above again).Lastly, substitute the values (1, 2) into the equation ⇒ 2 = 1/1 + 1 (LHS = RHS!) ⇒ the graph passes through this point!

P.S. Don't assume that the graph will always pass through that dot in your question! Sometimes the graph passes to it's left/right/top/bottom - always sub in its coordinates to check!

2ii.

never cuts x-axis but as , .

the curve passes through (0,1).

The curve has no maximum or minimum value.

and the curve passes through the given point!Once again, EMaths students will recall the shape of the graph of (they all intercept the

y-axis aty=1 sincea^{0}is always 1 and look similar in shape regardless of the value ofa, as long asais positive.So the only thing left to do is to substitute the values (1, 2) into the equation ⇒ 2 = 2

^{1}(LHS = RHS!) ⇒ the graph passes through this point!Poor candidate in your picture. He has written something meaningful, not just freaking with abc's.

Miss Loi too thinks that he deserves some sympathy marks for his back-to-basics description - to highlight the little things in life that we tend to take for granted

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oh dear. Line 3: from the negative x-axis:

(I wonder why T must be placed next to Y.)

Corrected for you Fatty fingers?

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*Creeps in silently to add some diagrams and explanations to

fggffggf's answer to improve clarity*曜

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Actually it was a typo, the problem with lighting typing.

Oh, and from this post on, I will identify myself as Li-sa and you might see my Li-sa footprints on some other blogs, like on squareCircleZ.

The blog I originally had will be shut down soon so no website link is given here.

Miss Loi, you don't have to creep in silently. Utmost silence looms like a thief.