Hmmm ... this question requires a bit of 'eye power' ...
This means the meter will start at ₩2, jumps to ₩4 (at 100 m), jumps to ₩6 (between 100-200 m), jumps to ₩8 (at 200 m) …
... which means that the 100 m mark occurs right at the start of the 2^{nd} 100 m. Similarly the 200 m mark occurs right at the start of the 3^{rd} 100 m.
So at which '100 m' do you think the 3 km is at? Probably it would've been clearer to put 0-99 m, 100-199 m, 200-299 m ... on the fare table but then this is a Korean taxi we're tallking about 😛
Also, you managed to put down n^{2} − n + 2 like a flash of lightning. Care to share the pattern you used to arrive at it (but then it's kinda obvious now isn't it? :P)
Total fare = Sum of all the meter readings from the very first reading to the final displayed reading.
From the above, the total fare payable is the sum of all meter readings all the way from the very first one i.e. 2 to the final one displayed (not just the sum of the final 100 m row alone), else it won't be called 당근 Taxi Company for nothing 😛
Sadly, my sis would've told us excitedly about all her shopping exploits by now if she had been shopping at Dongdaemun 🙁
]]>2) it is observed that at the (n−1)^{th} 100 meter, final meter reading =
Also, at the (n−1)^{th} 100 meter, no of meter readings = (n−1)
In this AP, number of terms= n
hence total sum of meter readings=
at 30km, total fare= 15(872)+872=13952 won.
aiya 绰绰有余 la. can stop at Dongdaemun shop abit somemore 😛
]]>Sigh ... think my sis sometimes misses her H2 maths a bit too much.
*hangs up*
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