Comments on: The 阴阳眼 Of Plane Geometry

By: Jukie Primestein

Jukie Primestein — Fri, 29 Oct 2010 20:27:53 +0000

Miss Loi I like the way u express your proof with diagrams. Thanks for the geometry formula sheet I have never seen one. With the diagrams of both I will be able to teach geometry even to the youths who can't read.

By: Belle

Belle — Wed, 27 Oct 2010 18:00:14 +0000

Plane geog! Click! http://www.exampaper.com.sg/tuition-notes/a-maths-tips/the-yin-yang-eye-of-plane-geometry

By: Miss Loi

Miss Loi — Mon, 30 Mar 2009 15:26:43 +0000

JH: For your conclusion to be true, AC & BD have to be diameters of the circle in order for ABC & BCD to be semi-circles, but this is not given in the question.

Also note that though CE is tangent to the circle at C, it's not stated in the question that AC is ⊥ to CE, so we can't assume AC to be a diameter using the radius ⊥ tangent property either.

However, do share with Miss Loi any alternative method should your own 阴阳眼 happens to reveal something different

By: JH

JH — Mon, 30 Mar 2009 14:18:09 +0000

Erm for the 4th question,is it possible to conclude that
angle ABC=angle BCD=90 degree by using the right angle in semi circle theorem?

By: Calvin

Calvin — Sun, 28 Dec 2008 04:44:16 +0000

Okay. So my vision's still working perfectly

By: Miss Loi

Miss Loi — Sun, 28 Dec 2008 04:04:28 +0000

Thanks Calvin for pointing out the typos.

Yes in Qn 1, SR should be the angle bisector and the said ratio in the question has been amended to .

And it's not you but Miss Loi who was actually hallucinating when she was typing this whole chunk of swollen-fingers-inducing article many weeks ago

Do ring the bell loud loud again should you spot any more typos.

By: Calvin

Calvin — Sun, 28 Dec 2008 03:44:40 +0000

Err okay maybe this is a little late to say this, but there seems to be a small typo with question 1...

The question reads: "In the given figure, RT = RQ. If SQ bisects ∠PRQ" when it kinda looks more like SR bisecting ∠PRQ...

Part 2:
The question asks to show that (RT/RQ) = (SP/SQ)... but isn't RT = RQ?

I dunno, maybe I'm just hallucinating the mistakes or something :S

By: Miss Loi

Miss Loi — Tue, 09 Dec 2008 17:07:42 +0000

Anoneemers: Yes there should be more than one way to prove L in that kite-ish diagram in 9(i). Did your 阴阳眼 saw the same stuffs as Miss Loi's? Crazyhamster: Believe it or not, it was found via searching for "stressed student" in Google Images! Google may have picked you as the iconic symbol of all stressed Singaporean students!

By: crazyhamster

crazyhamster — Mon, 08 Dec 2008 17:02:47 +0000

whoa whoa whoa, when was that photo taken

By: Anoneemers

Anoneemers — Sun, 26 Oct 2008 07:22:39 +0000

There's another 阴阳眼 question on Friday which is the 9(i) proving L=4sinθ-2cosθ (p.s. this is not plane geometry) and alot of people dunno how to prove because they see right angles on 2 sides and then they thought is kite =.= then i was thinking if its a kite then L=2cm which is impossible...
So i drew many many lines n eventually got the answer