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	<title>Comments on: Kinematics &#8211; This Is E-Maths Not A-Maths!</title>
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	<description>Sassy O Level Maths Tuition, Questions &#38; Tips from Singapore&#039;s Favourite Private Tutor</description>
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		<title>By: Nash</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-30777</link>
		<dc:creator>Nash</dc:creator>
		<pubDate>Mon, 12 Oct 2009 13:47:24 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-30777</guid>
		<description>At a levels.. this is about all the info you get and its  a physics mcq question...So the information is sufficient actually. ^_^

Moral of the story, If u cant handle this,don&#039;t choose A levels go poly! Trust me its not worth the tears of blood shed X_X.</description>
		<content:encoded><![CDATA[<p>At a levels.. this is about all the info you get and its  a physics mcq question...So the information is sufficient actually. ^_^</p>
<p>Moral of the story, If u cant handle this,don't choose A levels go poly! Trust me its not worth the tears of blood shed X_X.</p>
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		<title>By: Joanne</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-30771</link>
		<dc:creator>Joanne</dc:creator>
		<pubDate>Mon, 12 Oct 2009 07:43:41 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-30771</guid>
		<description>i think that the information given is not enough T.T</description>
		<content:encoded><![CDATA[<p>i think that the information given is not enough T.T</p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-431</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Tue, 10 Jul 2007 16:53:38 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-431</guid>
		<description>Great work Ms Lala! Can Miss Loi assume that you mental calculations were done with the help of the graph?

Next time don&#039;t forget to write down your working (even though Miss Loi knows they&#039;re all on your head!).

So to complete your answers with some explanations:

1. In a speed/time graph, the distance covered in 10 sec will be the area under the graph bounded by 0 &#8804; &lt;var&gt;t&lt;/var&gt; &#8804; 10, which is the area of a trapezium (see shaded portion below). 

&lt;img src=&quot;http://www.exampaper.com.sg/blog/wp-content/uploads/2007/07/kinematics-emaths-answer-0.jpg&quot; alt=&quot;Answer 1&quot; /&gt;

Hence solve for:
(1/2)(2 + &lt;var&gt;u&lt;/var&gt;)(10) = 60

Hope students still remember the formula to find the area of a trapezium!

2. Let the speed be &lt;var&gt;x&lt;/var&gt; at 16 seconds. If you draw some lines on the relevant coordinates, you&#039;ll actually come face to face with two similar triangles (see the shaded portion below):

&lt;img src=&quot;http://www.exampaper.com.sg/blog/wp-content/uploads/2007/07/kinematics-emaths-answer-1.jpg&quot; alt=&quot;Answer 2&quot; /&gt;

Hence solve for &lt;var&gt;x&lt;/var&gt;:
(10-&lt;var&gt;x&lt;/var&gt;)/&lt;var&gt;x&lt;/var&gt; = 1/14

3. Hope Miss Loi&#039;s sketching skills are good enough to illustrate your &#039;descriptive&#039; answers for clarity:

&lt;img src=&quot;http://www.exampaper.com.sg/blog/wp-content/uploads/2007/07/kinematics-emaths-answers-2.jpg&quot; alt=&quot;Answer 3&quot; /&gt;

As mentioned in the main entry, students really, really need to understand the concepts of gradients in different graphs.

Also remember to label all points on the axes (i.e. distance) else marks might be lost!</description>
		<content:encoded><![CDATA[<p>Great work Ms Lala! Can Miss Loi assume that you mental calculations were done with the help of the graph?</p>
<p>Next time don't forget to write down your working (even though Miss Loi knows they're all on your head!).</p>
<p>So to complete your answers with some explanations:</p>
<p>1. In a speed/time graph, the distance covered in 10 sec will be the area under the graph bounded by 0 &le; <var>t</var> &le; 10, which is the area of a trapezium (see shaded portion below). </p>
<p><img src="http://www.exampaper.com.sg/blog/wp-content/uploads/2007/07/kinematics-emaths-answer-0.jpg" alt="Answer 1" /></p>
<p>Hence solve for:<br />
(1/2)(2 + <var>u</var>)(10) = 60</p>
<p>Hope students still remember the formula to find the area of a trapezium!</p>
<p>2. Let the speed be <var>x</var> at 16 seconds. If you draw some lines on the relevant coordinates, you'll actually come face to face with two similar triangles (see the shaded portion below):</p>
<p><img src="http://www.exampaper.com.sg/blog/wp-content/uploads/2007/07/kinematics-emaths-answer-1.jpg" alt="Answer 2" /></p>
<p>Hence solve for <var>x</var>:<br />
(10-<var>x</var>)/<var>x</var> = 1/14</p>
<p>3. Hope Miss Loi's sketching skills are good enough to illustrate your 'descriptive' answers for clarity:</p>
<p><img src="http://www.exampaper.com.sg/blog/wp-content/uploads/2007/07/kinematics-emaths-answers-2.jpg" alt="Answer 3" /></p>
<p>As mentioned in the main entry, students really, really need to understand the concepts of gradients in different graphs.</p>
<p>Also remember to label all points on the axes (i.e. distance) else marks might be lost!</p>
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		<title>By: Ms Lala</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-426</link>
		<dc:creator>Ms Lala</dc:creator>
		<pubDate>Mon, 09 Jul 2007 16:39:46 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-426</guid>
		<description>1. u = 10 m/s
2. 9 and 1/3 m/s
3a. starting from zero, a curved line with an increasing slope, followed by a straight line with constant slope, then lastly a curved line with a decreasing slope.
3b. horizontal line at a=0.8, followed by horizontal line at a=0, lastly horizontal line at a= -2/3

hopefully my mental calculations aren&#039;t too hopelessly wrong.</description>
		<content:encoded><![CDATA[<p>1. u = 10 m/s<br />
2. 9 and 1/3 m/s<br />
3a. starting from zero, a curved line with an increasing slope, followed by a straight line with constant slope, then lastly a curved line with a decreasing slope.<br />
3b. horizontal line at a=0.8, followed by horizontal line at a=0, lastly horizontal line at a= -2/3</p>
<p>hopefully my mental calculations aren't too hopelessly wrong.</p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-425</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Mon, 09 Jul 2007 16:37:07 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-425</guid>
		<description>winston ... ummm ... don&#039;t think you&#039;re lucky this time. Read the &lt;span class=&quot;highlight&quot;&gt;red text&lt;/span&gt; dude!</description>
		<content:encoded><![CDATA[<p>winston ... ummm ... don't think you're lucky this time. Read the <span class="highlight">red text</span> dude!</p>
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		<title>By: winston</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-423</link>
		<dc:creator>winston</dc:creator>
		<pubDate>Mon, 09 Jul 2007 11:10:57 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/kinematics-this-is-e-maths-not-a-maths#comment-423</guid>
		<description>1st answer is 4.
2nd one if i am lucky is 4 - 1/16 = 64/16 - 1/16= 63/16 = 3 15/16!

i dont know the rest :P how are you going to release ans?
(i&#039;m one of the few who don&#039;t take amaths.geez..)</description>
		<content:encoded><![CDATA[<p>1st answer is 4.<br />
2nd one if i am lucky is 4 - 1/16 = 64/16 - 1/16= 63/16 = 3 15/16!</p>
<p>i dont know the rest <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_razz.gif' alt=':P' class='wp-smiley' />  how are you going to release ans?<br />
(i'm one of the few who don't take amaths.geez..)</p>
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