<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: Inglourious *BEEP* Chapter One: The Crazy Cold Storage Aunty</title>
	<atom:link href="http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty/feed" rel="self" type="application/rss+xml" />
	<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty</link>
	<description>Sassy O Level Maths Tuition, Questions &#38; Tips from Singapore&#039;s Favourite Private Tutor</description>
	<lastBuildDate>Sun, 05 Feb 2012 17:08:39 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	
<xhtml:meta xmlns:xhtml="http://www.w3.org/1999/xhtml" name="robots" content="noindex" />
	<item>
		<title>By: munak</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30608</link>
		<dc:creator>munak</dc:creator>
		<pubDate>Tue, 06 Oct 2009 18:58:54 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30608</guid>
		<description>you is rite ms.loi, thats me on plurk</description>
		<content:encoded><![CDATA[<p>you is rite ms.loi, thats me on plurk</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: mathslover</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30313</link>
		<dc:creator>mathslover</dc:creator>
		<pubDate>Tue, 29 Sep 2009 17:44:28 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30313</guid>
		<description>I&#039;m the first victim because the others never try!!! :(

我知错了。:( I try to solve the Sadako Loi problem k? 不要再来找我了。</description>
		<content:encoded><![CDATA[<p>I'm the first victim because the others never try!!! <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_sad.gif' alt=':(' class='wp-smiley' /> </p>
<p>我知错了。:( I try to solve the Sadako Loi problem k? 不要再来找我了。</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30300</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Tue, 29 Sep 2009 11:39:44 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30300</guid>
		<description>&lt;b&gt;munak:&lt;/b&gt; Are you asrar in Plurk???

&lt;b&gt;mathslover:&lt;/b&gt; Marked your workings. Aiyooo so many careless mistakes! Think you&#039;re the first victim of Sadako Loi&#039;s Curse!

&lt;b&gt;a_x:&lt;/b&gt; Sadly, respect for aunties was the outcome of the day, and the poor cashier really had no choice but to apologize to the &lt;em&gt;young &amp; gracious&lt;/em&gt; Miss Loi profusely.

&lt;b&gt;Stan:&lt;/b&gt; Ooi don&#039;t be rude to aunties here! This is an aunty-friendly blog! *BEEP*!!!</description>
		<content:encoded><![CDATA[<p><b>munak:</b> Are you asrar in Plurk???</p>
<p><b>mathslover:</b> Marked your workings. Aiyooo so many careless mistakes! Think you're the first victim of Sadako Loi's Curse!</p>
<p><b>a_x:</b> Sadly, respect for aunties was the outcome of the day, and the poor cashier really had no choice but to apologize to the <em>young &#038; gracious</em> Miss Loi profusely.</p>
<p><b>Stan:</b> Ooi don't be rude to aunties here! This is an aunty-friendly blog! *BEEP*!!!</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Stan</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30166</link>
		<dc:creator>Stan</dc:creator>
		<pubDate>Sat, 26 Sep 2009 07:53:41 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30166</guid>
		<description>Ja!! Did you give the siao cha bo a piece of your mind? Or did you just retort: hurry *BEEP* up you *BEEP*?</description>
		<content:encoded><![CDATA[<p>Ja!! Did you give the siao cha bo a piece of your mind? Or did you just retort: hurry *BEEP* up you *BEEP*?</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: a_x</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30145</link>
		<dc:creator>a_x</dc:creator>
		<pubDate>Sat, 26 Sep 2009 00:19:01 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30145</guid>
		<description>Put the math aside, I&#039;m more curious about what happened to the crazy aunty? You smashed her with that bottle of barley drink? Seriously, though, the cashier didn&#039;t give in &amp; serve her instead of you, right?</description>
		<content:encoded><![CDATA[<p>Put the math aside, I'm more curious about what happened to the crazy aunty? You smashed her with that bottle of barley drink? Seriously, though, the cashier didn't give in &amp; serve her instead of you, right?</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: mathslover</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30128</link>
		<dc:creator>mathslover</dc:creator>
		<pubDate>Fri, 25 Sep 2009 17:21:23 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30128</guid>
		<description>*and shouldn&#039;t have complained about Sadako Loi*

2) F = kt&lt;sup&gt;&#8722;2&lt;/sup&gt;
When t is tripled,
New F = k(3t)&lt;sup&gt;&#8722;2&lt;/sup&gt;
New F = (1/9)kt&lt;sup&gt;&#8722;2&lt;/sup&gt;
New F = (1/9)F
Percentage change = change / original x 100%
= &#8722;(8/9)F / F x 100% = &#8722;0.889%

&lt;div class=&quot;highlight&quot;&gt;

&lt;strong&gt;Miss Loi:&lt;/strong&gt; This part is actually a test on your concept of &lt;a href=&quot;/tag/percentages&quot; rel=&quot;nofollow&quot;&gt;Percentages&lt;/a&gt; - a very basic Sec 1 topic that sadly managed to caught many students out.

After correcting your careless mistake in &lt;a href=&quot;#comment-30126 rel=&quot;nofollow&quot;&gt;Comment #2&lt;/a&gt;, you&#039;re right to list that:
&lt;ul&gt;
&lt;li&gt;Original &lt;m&gt;F = k/t^2&lt;/li&gt;
&lt;li&gt;New &lt;m&gt;F = k/(3t)^2 = (1/9)(k/t^2) = {1/9}F&lt;/m&gt;
&lt;/ul&gt;

So the change in &lt;var&gt;F&lt;/var&gt; = New &lt;var&gt;F&lt;/var&gt; &#8722; New &lt;var&gt;F&lt;/var&gt; = &lt;m&gt;({1/9}-1)F = -{8/9}F&lt;/m&gt;
&#8756; % change 
= (change in &lt;var&gt;F&lt;/var&gt;/ original &lt;var&gt;F&lt;/var&gt;) x 100%
= &lt;m&gt;-{{8/9}F}/F&lt;/m&gt; &#215; 100%
&#8776; &#8722;88.9%

So when &lt;var&gt;t&lt;/var&gt; is tripled, &lt;var&gt;F&lt;/var&gt; will &lt;strong&gt;decrease&lt;/strong&gt; by 88.9% &#8594; not 11.1%, or 800%, and most certainly NOT a Sadako Loi-induced 0.889%!!!!!!!!!!!!!!! 

&lt;div class=&quot;attention&quot;&gt;

&lt;img src=&quot;http://www.exampaper.com.sg/blog/wp-content/themes/exampaper/images/attention.gif&quot; alt=&quot;attention&quot;&gt; On hindsight it would&#039;ve served a greater purpose if this part of the question had been changed to &quot;Find the percentage change in &lt;var&gt;F&lt;/var&gt; when &lt;var&gt;t&lt;/var&gt; is &lt;em&gt;reduced&lt;/em&gt; by 3 times&quot; to emphasize the importance of the formula: &lt;strong&gt;% change = change / original x 100%&lt;/strong&gt;.

So in such a case, what would the % increase of &lt;var&gt;F&lt;/var&gt; be? 900%? 800%? 90%????? 

&lt;/div&gt;

&lt;/div&gt;

Sigh.. not going to check le...</description>
		<content:encoded><![CDATA[<p>*and shouldn't have complained about Sadako Loi*</p>
<p>2) F = kt<sup>&minus;2</sup><br />
When t is tripled,<br />
New F = k(3t)<sup>&minus;2</sup><br />
New F = (1/9)kt<sup>&minus;2</sup><br />
New F = (1/9)F<br />
Percentage change = change / original x 100%<br />
= &minus;(8/9)F / F x 100% = &minus;0.889%</p>
<div class="highlight">
<p><strong>Miss Loi:</strong> This part is actually a test on your concept of <a href="/tag/percentages" rel="nofollow">Percentages</a> - a very basic Sec 1 topic that sadly managed to caught many students out.</p>
<p>After correcting your careless mistake in <a href="#comment-30126 rel="nofollow">Comment #2</a>, you're right to list that:</p>
<ul>
<li>Original <m>F = k/t^2</m></li>
<li>New <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_961_6c882a8404a35651a01b0078f052feee.png" style="vertical-align:-39px; display: inline-block ;" alt="F = k/(3t)^2 = (1/9)(k/t^2) = {1/9}F" title="F = k/(3t)^2 = (1/9)(k/t^2) = {1/9}F"/>
</li>
</ul>
<p>So the change in <var>F</var> = New <var>F</var> &minus; New <var>F</var> = <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_971_60afd3c07f73f36d28bf4d6885c3173e.png" style="vertical-align:-29px; display: inline-block ;" alt="({1/9}-1)F = -{8/9}F" title="({1/9}-1)F = -{8/9}F"/><br />
&there4; % change<br />
= (change in <var>F</var>/ original <var>F</var>) x 100%<br />
= <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_2fb42430f3d9614e11a65164b5f0b434.png" style="vertical-align:-14px; display: inline-block ;" alt="-{{8/9}F}/F" title="-{{8/9}F}/F"/> &times; 100%<br />
&asymp; &minus;88.9%</p>
<p>So when <var>t</var> is tripled, <var>F</var> will <strong>decrease</strong> by 88.9% &rarr; not 11.1%, or 800%, and most certainly NOT a Sadako Loi-induced 0.889%!!!!!!!!!!!!!!! </p>
<div class="attention">
<p><img src="http://www.exampaper.com.sg/blog/wp-content/themes/exampaper/images/attention.gif" alt="attention"/> On hindsight it would've served a greater purpose if this part of the question had been changed to "Find the percentage change in <var>F</var> when <var>t</var> is <em>reduced</em> by 3 times" to emphasize the importance of the formula: <strong>% change = change / original x 100%</strong>.</p>
<p>So in such a case, what would the % increase of <var>F</var> be? 900%? 800%? 90%????? </p>
</div>
</div>
<p>Sigh.. not going to check le...</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: mathslover</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30127</link>
		<dc:creator>mathslover</dc:creator>
		<pubDate>Fri, 25 Sep 2009 17:13:16 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30127</guid>
		<description>Ahh just realised I wasted too much time. 

&quot;F inversely proportional to t squared means F = kt&lt;sup&gt;&#8722;2&lt;/sup&gt; means t cannot be 0.&quot; can be used to explain why all your graphs are wrong except IV already... 

*really shouldn&#039;t have viewed Sadako Loi&#039;s video so late that night*</description>
		<content:encoded><![CDATA[<p>Ahh just realised I wasted too much time. </p>
<p>"F inversely proportional to t squared means F = kt<sup>&minus;2</sup> means t cannot be 0." can be used to explain why all your graphs are wrong except IV already... </p>
<p>*really shouldn't have viewed Sadako Loi's video so late that night*</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: mathslover</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30126</link>
		<dc:creator>mathslover</dc:creator>
		<pubDate>Fri, 25 Sep 2009 17:08:01 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30126</guid>
		<description>Miss Loi turn from story telling to manga drawing le... what next? :P

Question hijacking time! 

1) IV 
- I and II definitely out, inversely proportional means as t goes up F goes down. 
- V definitely out because inversely proportional to square of t means the F/t graph cannot be straight line. 
- III is out because F inversely proportional to t squared means F = kt&lt;sup&gt;&#8722;2&lt;/sup&gt; means t cannot be 0. 

Hence by elimination of impossible answers, the answer of IV is obtained. :P 

&lt;div class=&quot;highlight&quot;&gt;

&lt;strong&gt;Miss Loi:&lt;/strong&gt; Yes the question states that &quot;&lt;var&gt;F&lt;/var&gt; is &lt;strong&gt;&lt;em&gt;inversely&lt;/em&gt;&lt;/strong&gt; proportional to the &lt;strong&gt;square of &lt;var&gt;x&lt;/var&gt;&lt;/strong&gt;&quot;.

Putting this English statement in mathematical context
&#8658; &lt;var&gt;F&lt;/var&gt;&#8593;, &lt;var&gt;x&lt;/var&gt;&lt;sup&gt;2&lt;/sup&gt;&#8595; &#8660; &lt;var&gt;F&lt;/var&gt;&#8595;, &lt;var&gt;x&lt;/var&gt;&lt;sup&gt;2&lt;/sup&gt;&#8593; (&#8658; Graphs I &amp; II are out!)
&#8658; &lt;var&gt;F&lt;/var&gt; &#8733; &lt;m&gt;1/x^2&lt;/m&gt; (by definition)
&#8658; &lt;var&gt;F&lt;/var&gt; = &lt;m&gt;k/x^2&lt;/m&gt;

If you&#039;re an upper sec student who&#039;s already familiar with the various sketches of important &lt;a href=&quot;/tag/graphs&quot; rel=&quot;nofollow&quot;&gt;graphs&lt;/a&gt;, you should &lt;em&gt;straightaway&lt;/em&gt; be able to identify the graph of &lt;m&gt;y=a/x^2&lt;/m&gt;, jump up from your seat and scream &quot;&lt;i&gt;It&#039;s IV! It&#039;s IV! IT&#039;S IV&lt;/i&gt;&quot; excitedly like a &lt;i&gt;siao cha/ta boh&lt;/i&gt; (to the chagrin of those around you). 

Else you may follow &lt;b&gt;mathslover&lt;/b&gt;&#039;s wisdom of elimination and/or her &lt;a href=&quot;#comment-30127&quot; rel=&quot;nofollow&quot;&gt;comment below&lt;/a&gt; to arrive at the same conclusion.

P.S. It&#039;s good to write out the &lt;var&gt;F&lt;/var&gt; = &lt;m&gt;k/x^2&lt;/m&gt; expression coz it&#039;s easy to forget that we&#039;re dealing with a &lt;strong&gt;square of &lt;var&gt;x&lt;/var&gt;&lt;/strong&gt; here, as many of us may already have the image of &lt;var&gt;F&lt;/var&gt; = &lt;m&gt;k/x&lt;/m&gt; from textbooks/formula sheets burnt &lt;i&gt;deep deep&lt;/i&gt; in our minds.

&lt;/div&gt;

2) F = kt&lt;sup&gt;&#8722;2&lt;/sup&gt;
When t is tripled, 
New F = k(3t)&lt;sup&gt;&#8722;2&lt;/sup&gt;
New F = 9kt&lt;sup&gt;&#8722;2&lt;/sup&gt; 
&lt;span class=&quot;highlight&quot;&gt;&#8594; Aiyooo! Tsk tsk! Luckily you managed to 悬崖勒马 &lt;a href=&quot;#comment-30128&quot; rel=&quot;nofollow&quot;&gt;below&lt;/a&gt; BUT ...&lt;/span&gt;

&lt;div class=&quot;highlight&quot;&gt;

&lt;del&gt;New F = 9F&lt;/del&gt; 
&lt;del&gt;Percentage change = change / original &#215; 100%&lt;/del&gt;
&lt;del&gt;= 8F / F &#215; 100% = 800%&lt;/del&gt;

*Puts up WRONG WORKING tape* Move along now ... see &lt;a href=&quot;#comment-30128&quot; rel=&quot;nofollow&quot;&gt;corrected workings&lt;/a&gt; below!

&lt;/div&gt;

3) When t = 70, F = 0.1. 
By substituting, 
0.1 = k (70&lt;sup&gt;&#8722;2&lt;/sup&gt;) 
0.1 x 4900 = k
k = 490

3i) F = 490t&lt;sup&gt;&#8722;2&lt;/sup&gt;

When F = 0.1/2 = 0.05, Miss Loi will start to challenge the law by drinking unpaid barley water. 

F = 490t&lt;sup&gt;&#8722;2&lt;/sup&gt; = 0.05
490 = 0.05t&lt;sup&gt;2&lt;/sup&gt;
t&lt;sup&gt;2&lt;/sup&gt; = 490 / 0.05 = 9800
t = 98.995s = 99.0s (3.s.f)

3ii) t = 99.0s

&lt;div class=&quot;highlight&quot;&gt;

Part 3 is one of the two typically standard kinds of &lt;a href=&quot;/tag/variations&quot; rel=&quot;nofollow&quot;&gt;proportion/variations&lt;/a&gt; questions (the other kind being something like &lt;a href=&quot;/questions/e-maths/algebra-whos-the-lazy-bugger&quot; rel=&quot;nofollow&quot;&gt;this&lt;/a&gt; that you can expect to see in your O-Level E-Maths Paper 1.

As shown by &lt;b&gt;mathslover&lt;/b&gt;&#039;s workings above, one can see that it&#039;s important to read the statement in the question carefully (i.e. pick out the critical words like &quot;inversely&quot;, &quot;square of &lt;var&gt;x&lt;/var&gt;&quot;, &quot;&lt;var&gt;F&lt;/var&gt; falls to half of this value&quot; etc.) in order to obtain the expression (&lt;m&gt;F = k/x^2&lt;/m&gt;) and subsequently the value of &lt;var&gt;k&lt;/var&gt; correct from the start.

After which it&#039;s simply sub, sub, sub in the given values to find that Miss Loi has about half a minute to take corrective action to prevent irreversible damage to her skin!

&lt;/div&gt;

Miss Loi ah, next time don&#039;t wait till last minute then buy water...</description>
		<content:encoded><![CDATA[<p>Miss Loi turn from story telling to manga drawing le... what next? <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_razz.gif' alt=':P' class='wp-smiley' /> </p>
<p>Question hijacking time! </p>
<p>1) IV<br />
- I and II definitely out, inversely proportional means as t goes up F goes down.<br />
- V definitely out because inversely proportional to square of t means the F/t graph cannot be straight line.<br />
- III is out because F inversely proportional to t squared means F = kt<sup>&minus;2</sup> means t cannot be 0. </p>
<p>Hence by elimination of impossible answers, the answer of IV is obtained. <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_razz.gif' alt=':P' class='wp-smiley' />  </p>
<div class="highlight">
<p><strong>Miss Loi:</strong> Yes the question states that "<var>F</var> is <strong><em>inversely</em></strong> proportional to the <strong>square of <var>x</var></strong>".</p>
<p>Putting this English statement in mathematical context<br />
&rArr; <var>F</var>&uarr;, <var>x</var><sup>2</sup>&darr; &hArr; <var>F</var>&darr;, <var>x</var><sup>2</sup>&uarr; (&rArr; Graphs I &#038; II are out!)<br />
&rArr; <var>F</var> &prop; <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_f72f4ec30d901a58ad00d6962e0f220d.png" style="vertical-align:-21px; display: inline-block ;" alt="1/x^2" title="1/x^2"/> (by definition)<br />
&rArr; <var>F</var> = <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_c7061fbf2470f259ae7541f717d29494.png" style="vertical-align:-21px; display: inline-block ;" alt="k/x^2" title="k/x^2"/></p>
<p>If you're an upper sec student who's already familiar with the various sketches of important <a href="/tag/graphs" rel="nofollow">graphs</a>, you should <em>straightaway</em> be able to identify the graph of <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_558734631e3ced5cc017c3b14e8410dd.png" style="vertical-align:-21px; display: inline-block ;" alt="y=a/x^2" title="y=a/x^2"/>, jump up from your seat and scream "<i>It's IV! It's IV! IT'S IV</i>" excitedly like a <i>siao cha/ta boh</i> (to the chagrin of those around you). </p>
<p>Else you may follow <b>mathslover</b>'s wisdom of elimination and/or her <a href="#comment-30127" rel="nofollow">comment below</a> to arrive at the same conclusion.</p>
<p>P.S. It's good to write out the <var>F</var> = <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_c7061fbf2470f259ae7541f717d29494.png" style="vertical-align:-21px; display: inline-block ;" alt="k/x^2" title="k/x^2"/> expression coz it's easy to forget that we're dealing with a <strong>square of <var>x</var></strong> here, as many of us may already have the image of <var>F</var> = <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_a260708d270e0bde90e5f5a418d8da22.png" style="vertical-align:-14px; display: inline-block ;" alt="k/x" title="k/x"/> from textbooks/formula sheets burnt <i>deep deep</i> in our minds.</p>
</div>
<p>2) F = kt<sup>&minus;2</sup><br />
When t is tripled,<br />
New F = k(3t)<sup>&minus;2</sup><br />
New F = 9kt<sup>&minus;2</sup><br />
<span class="highlight">&rarr; Aiyooo! Tsk tsk! Luckily you managed to 悬崖勒马 <a href="#comment-30128" rel="nofollow">below</a> BUT ...</span></p>
<div class="highlight">
<p><del>New F = 9F</del><br />
<del>Percentage change = change / original &times; 100%</del><br />
<del>= 8F / F &times; 100% = 800%</del></p>
<p>*Puts up WRONG WORKING tape* Move along now ... see <a href="#comment-30128" rel="nofollow">corrected workings</a> below!</p>
</div>
<p>3) When t = 70, F = 0.1.<br />
By substituting,<br />
0.1 = k (70<sup>&minus;2</sup>)<br />
0.1 x 4900 = k<br />
k = 490</p>
<p>3i) F = 490t<sup>&minus;2</sup></p>
<p>When F = 0.1/2 = 0.05, Miss Loi will start to challenge the law by drinking unpaid barley water. </p>
<p>F = 490t<sup>&minus;2</sup> = 0.05<br />
490 = 0.05t<sup>2</sup><br />
t<sup>2</sup> = 490 / 0.05 = 9800<br />
t = 98.995s = 99.0s (3.s.f)</p>
<p>3ii) t = 99.0s</p>
<div class="highlight">
<p>Part 3 is one of the two typically standard kinds of <a href="/tag/variations" rel="nofollow">proportion/variations</a> questions (the other kind being something like <a href="/questions/e-maths/algebra-whos-the-lazy-bugger" rel="nofollow">this</a> that you can expect to see in your O-Level E-Maths Paper 1.</p>
<p>As shown by <b>mathslover</b>'s workings above, one can see that it's important to read the statement in the question carefully (i.e. pick out the critical words like "inversely", "square of <var>x</var>", "<var>F</var> falls to half of this value" etc.) in order to obtain the expression (<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_89df5b0bad60ee26a1da36daf3b68209.png" style="vertical-align:-21px; display: inline-block ;" alt="F = k/x^2" title="F = k/x^2"/>) and subsequently the value of <var>k</var> correct from the start.</p>
<p>After which it's simply sub, sub, sub in the given values to find that Miss Loi has about half a minute to take corrective action to prevent irreversible damage to her skin!</p>
</div>
<p>Miss Loi ah, next time don't wait till last minute then buy water...</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: munak</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30104</link>
		<dc:creator>munak</dc:creator>
		<pubDate>Fri, 25 Sep 2009 09:22:54 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-30104</guid>
		<description>hahahaha  i like how u narrate the story, very creative! and looking at all these maths questions, ahhh the school days</description>
		<content:encoded><![CDATA[<p>hahahaha  i like how u narrate the story, very creative! and looking at all these maths questions, ahhh the school days</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-36900</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Fri, 25 Sep 2009 08:14:02 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/e-maths/inglourious-beep-chapter-one-the-crazy-cold-storage-aunty#comment-36900</guid>
		<description>&lt;span class=&quot;topsy_trackback_comment&quot;&gt;&lt;span class=&quot;topsy_twitter_username&quot;&gt;&lt;span class=&quot;topsy_trackback_content&quot;&gt;The Crazy Cold Storage Aunty: http://bit.ly/1rKZwe&lt;/span&gt;&lt;/span&gt;</description>
		<content:encoded><![CDATA[<p><span class="topsy_trackback_comment"><span class="topsy_twitter_username"><span class="topsy_trackback_content">The Crazy Cold Storage Aunty: <a href="http://bit.ly/1rKZwe" rel="nofollow">http://bit.ly/1rKZwe</a></span></span></span></p>
]]></content:encoded>
	</item>
</channel>
</rss>

