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	<title>Comments on: I, Neighbour</title>
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	<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour</link>
	<description>Sassy O Level Maths Tuition, Questions &#38; Tips from Singapore&#039;s Favourite Private Tutor</description>
	<lastBuildDate>Mon, 30 Aug 2010 06:59:53 +0000</lastBuildDate>
	
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38260</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Wed, 11 Aug 2010 06:42:25 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38260</guid>
		<description>Thanks to all your help, Miss Loi thinks it&#039;s all settled now.

*fingers tightly crossed*

In other news, your &lt;a href=&quot;http://www.facebook.com/profile.php?id=100000259566886&amp;v=wall&quot; rel=&quot;nofollow&quot;&gt;good friend just said Hi&lt;/a&gt;.</description>
		<content:encoded><![CDATA[<p>Thanks to all your help, Miss Loi thinks it's all settled now.</p>
<p>*fingers tightly crossed*</p>
<p>In other news, your <a href="http://www.facebook.com/profile.php?id=100000259566886&#038;v=wall" rel="nofollow">good friend just said Hi</a>.</p>
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		<title>By: Nash</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38247</link>
		<dc:creator>Nash</dc:creator>
		<pubDate>Sun, 08 Aug 2010 13:33:42 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38247</guid>
		<description>why are we helping the neighbour? hmm.... considering your neighbours constant nagging its to help miss loi.. did you know.. noise pollution causes lack of concentration, fatigue, increased blood pressure,decreased efficiency and temporary or permanent deafness? so the faster he zips up the better ^_^</description>
		<content:encoded><![CDATA[<p>why are we helping the neighbour? hmm.... considering your neighbours constant nagging its to help miss loi.. did you know.. noise pollution causes lack of concentration, fatigue, increased blood pressure,decreased efficiency and temporary or permanent deafness? so the faster he zips up the better ^_^</p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38233</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Mon, 02 Aug 2010 06:42:14 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38233</guid>
		<description>Oh boy manhours again! But actually, it&#039;s a really handy method so it&#039;s worth going through &lt;a href=&quot;#comment-38199&quot; rel=&quot;nofollow&quot;&gt;mathslover&#039;s&lt;/a&gt; &amp; &lt;a href=&quot;#comment-38230&quot; rel=&quot;nofollow&quot;&gt;Nash&#039;s&lt;/a&gt; workings to understand it.

Once again, however, for the sake of those who wish to stick to what&#039;s been taught in school (or have your cher introduced manhours - anyone?),

From Part I, we know that we&#039;re left with 1/3 of the leak after 2 days
⇒ 3 men → 2 hours → 1/3 leak

However, on Day 3:
a new leak has been discover ⇒ 1+1/3 = 4/3 leak
and there&#039;s only 1 man to work for 2 hours 
⇒ 1 man → 2 hours → 1/3 &#247; 3 =  1/9 leak
 &lt;span class=&quot;fineprint highlight&quot;&gt;(less men do less work in the same amount of time, they are &lt;em&gt;directly&lt;/em&gt; proportional)&lt;/span&gt;

So on Day 4:
Amount of &#039;leak&#039; left: 4/3 &#8722; 1/9 = 11/9

We now take &lt;em&gt;any&lt;/em&gt; expression from Part I as our base for the final calculation. Since we&#039;re stuck with 4 hours on the last day, we chose the following for convenience:

3 men → 2 hours → 1/3 leak
1.5 men → 4 hours → 1/3 leak
&lt;span class=&quot;fineprint highlight&quot;&gt;(we first keep the leak constant to fix the hours)&lt;/span&gt;

We have 11/9 leak left to fix and this time we keep the hours constant,
1.5 &#215; 11/3 men → 4 hours → 1/3 &#215; 11/3 = 11/9 leak
&lt;span class=&quot;fineprint highlight&quot;&gt;(more work require more men in the same amount of time, they are &lt;em&gt;directly&lt;/em&gt; proportional)&lt;/span&gt;
5.5 men → 4 hours → 11/9 leak

As it&#039;s unlikely the contractor has a mutant half-human in his employee list, he&#039;ll need to send 6 men to finish the job in 4 hours on the last day (one of the men can afford slack a little to work at half-pace though ;) )

Miss Loi hopes this simple exercise will give everyone some practice in playing around with the &lt;strong&gt;Unitary Method&lt;/strong&gt; on questions with &lt;em&gt;3 variables&lt;/em&gt;, &lt;span class=&quot;highlight&quot;&gt;keeping one variable constant at a time&lt;/span&gt; in order to achieve your desired results.

Having said that, 
&lt;span class=&quot;superbig&quot;&gt;why are we helping John the Neighbour???!&lt;/span&gt;</description>
		<content:encoded><![CDATA[<p>Oh boy manhours again! But actually, it's a really handy method so it's worth going through <a href="#comment-38199" rel="nofollow">mathslover's</a> &#038; <a href="#comment-38230" rel="nofollow">Nash's</a> workings to understand it.</p>
<p>Once again, however, for the sake of those who wish to stick to what's been taught in school (or have your cher introduced manhours - anyone?),</p>
<p>From Part I, we know that we're left with 1/3 of the leak after 2 days<br />
⇒ 3 men → 2 hours → 1/3 leak</p>
<p>However, on Day 3:<br />
a new leak has been discover ⇒ 1+1/3 = 4/3 leak<br />
and there's only 1 man to work for 2 hours<br />
⇒ 1 man → 2 hours → 1/3 &divide; 3 =  1/9 leak<br />
 <span class="fineprint highlight">(less men do less work in the same amount of time, they are <em>directly</em> proportional)</span></p>
<p>So on Day 4:<br />
Amount of 'leak' left: 4/3 &minus; 1/9 = 11/9</p>
<p>We now take <em>any</em> expression from Part I as our base for the final calculation. Since we're stuck with 4 hours on the last day, we chose the following for convenience:</p>
<p>3 men → 2 hours → 1/3 leak<br />
1.5 men → 4 hours → 1/3 leak<br />
<span class="fineprint highlight">(we first keep the leak constant to fix the hours)</span></p>
<p>We have 11/9 leak left to fix and this time we keep the hours constant,<br />
1.5 &times; 11/3 men → 4 hours → 1/3 &times; 11/3 = 11/9 leak<br />
<span class="fineprint highlight">(more work require more men in the same amount of time, they are <em>directly</em> proportional)</span><br />
5.5 men → 4 hours → 11/9 leak</p>
<p>As it's unlikely the contractor has a mutant half-human in his employee list, he'll need to send 6 men to finish the job in 4 hours on the last day (one of the men can afford slack a little to work at half-pace though <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_wink.gif' alt=';)' class='wp-smiley' />  )</p>
<p>Miss Loi hopes this simple exercise will give everyone some practice in playing around with the <strong>Unitary Method</strong> on questions with <em>3 variables</em>, <span class="highlight">keeping one variable constant at a time</span> in order to achieve your desired results.</p>
<p>Having said that,<br />
<span class="superbig">why are we helping John the Neighbour???!</span></p>
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		<title>By: Nash</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38231</link>
		<dc:creator>Nash</dc:creator>
		<pubDate>Sat, 31 Jul 2010 06:33:43 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38231</guid>
		<description>then again they can just go fix his ceiling =X.. its probably the holes caused by the drill works from his side..</description>
		<content:encoded><![CDATA[<p>then again they can just go fix his ceiling =X.. its probably the holes caused by the drill works from his side..</p>
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		<title>By: Nash</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38230</link>
		<dc:creator>Nash</dc:creator>
		<pubDate>Fri, 30 Jul 2010 13:39:36 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38230</guid>
		<description>hmm... 
first part: 3days x 3 workers x 2 hours per day =&gt; 18 man hours 
on the third day originally: 1day x 3 workers x 2hours per day =&gt; 6 man hours
on the third day (without sick worker) : 6 man hours / 2 workers =&gt; 3 hours per worker

second part: since no work was done remaining labour to be done by worker =&gt; 6 man hours + 18 man hours(second leak) = 24 man hours
so the lonely worker completes 2 man hours of work on the third day. leaving 22 man hours of work left.

Since on the 4th day has a maximum time limit of 4hrs, min no. of workers to complete the sealing of miss loi&#039;s floor,(neighbor&#039;s &quot;best&quot; ceiling) =&gt; 5 (hence making 6 workers in total). Then again the neighbor can send as many workers as he can to get things done fast. 

Have a nice week Miss Loi ^_^</description>
		<content:encoded><![CDATA[<p>hmm...<br />
first part: 3days x 3 workers x 2 hours per day =&gt; 18 man hours<br />
on the third day originally: 1day x 3 workers x 2hours per day =&gt; 6 man hours<br />
on the third day (without sick worker) : 6 man hours / 2 workers =&gt; 3 hours per worker</p>
<p>second part: since no work was done remaining labour to be done by worker =&gt; 6 man hours + 18 man hours(second leak) = 24 man hours<br />
so the lonely worker completes 2 man hours of work on the third day. leaving 22 man hours of work left.</p>
<p>Since on the 4th day has a maximum time limit of 4hrs, min no. of workers to complete the sealing of miss loi's floor,(neighbor's "best" ceiling) =&gt; 5 (hence making 6 workers in total). Then again the neighbor can send as many workers as he can to get things done fast. </p>
<p>Have a nice week Miss Loi ^_^</p>
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		<title>By: mathslover</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38210</link>
		<dc:creator>mathslover</dc:creator>
		<pubDate>Thu, 29 Jul 2010 15:24:33 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38210</guid>
		<description>Go wreck havoc at his &#039;housewarming party&#039;. :P</description>
		<content:encoded><![CDATA[<p>Go wreck havoc at his 'housewarming party'. <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_razz.gif' alt=':P' class='wp-smiley' /> </p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38209</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Thu, 29 Jul 2010 13:45:09 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38209</guid>
		<description>That sounds very similar to what the neighbour living &lt;em&gt;below&lt;/em&gt; John has been complaining about all these years!</description>
		<content:encoded><![CDATA[<p>That sounds very similar to what the neighbour living <em>below</em> John has been complaining about all these years!</p>
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		<title>By: TJK</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38207</link>
		<dc:creator>TJK</dc:creator>
		<pubDate>Wed, 28 Jul 2010 14:06:18 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38207</guid>
		<description>i had also one such neighbor, thinking his house is number one, and keep on drilling his house once in two weeks, and a lot of debris fell down and had to spent money to repair it. So, it is still better to be on top of one &quot;such&quot; bad neighbor than be below</description>
		<content:encoded><![CDATA[<p>i had also one such neighbor, thinking his house is number one, and keep on drilling his house once in two weeks, and a lot of debris fell down and had to spent money to repair it. So, it is still better to be on top of one "such" bad neighbor than be below</p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38206</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Wed, 28 Jul 2010 05:33:13 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38206</guid>
		<description>Just happens that Miss Loi cannot use her kitchen taps again today :(</description>
		<content:encoded><![CDATA[<p>Just happens that Miss Loi cannot use her kitchen taps again today <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_sad.gif' alt=':(' class='wp-smiley' /> </p>
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		<title>By: John the Neighbour</title>
		<link>http://www.exampaper.com.sg/questions/e-maths/i-neighbour#comment-38205</link>
		<dc:creator>John the Neighbour</dc:creator>
		<pubDate>Wed, 28 Jul 2010 05:25:04 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/?p=1544#comment-38205</guid>
		<description>Unfortunately Day Three brought with it a series of misfortunes.

&lt;div class=&quot;question&quot;&gt;

&lt;span class=&quot;superbig&quot;&gt;PART II:&lt;/span&gt;

Before work even began today (i.e. the third day), another leak (similar to the first one) was discovered on her kitchen floor! I had a heated exchange with one of the remaining workers who dared suggest this new leak could be the result of &lt;em&gt;my&lt;/em&gt; continuous renovation activities, which is obviously untrue.

Because of this, the worker stormed out of the place leaving only one worker to work today.

To make matters worse, my uncooperative neighbour told me that she can only stay for &lt;span class=&quot;highlight&quot;&gt;two hours today, plus up to a maximum of 4 hours in an extra day tomorrow&lt;/span&gt;.

I called the contractor and since this scenario is too complicated for his &quot;failed PSLE&quot; brain, so he asked &lt;em&gt;me&lt;/em&gt; to calculate for him how many workers in total he needs to send on the last day (i.e. Day 4) in order to complete the job.

&lt;/div&gt;

I cannot accept this. What have I done to deserve this? Failing PSLE is not an excuse for not knowing &lt;a href=&quot;/tag/variations&quot; rel=&quot;nofollow&quot;&gt;proportion and variations&lt;/a&gt; to solve my urgent problem.

If you can solve this, I will &lt;i&gt;confirm chop stamp&lt;/i&gt; invite you to my housewarming party, where you can admire my flat, which will &lt;i&gt;confirm chop stamp&lt;/i&gt; be the best of the best.</description>
		<content:encoded><![CDATA[<p>Unfortunately Day Three brought with it a series of misfortunes.</p>
<div class="question">
<p><span class="superbig">PART II:</span></p>
<p>Before work even began today (i.e. the third day), another leak (similar to the first one) was discovered on her kitchen floor! I had a heated exchange with one of the remaining workers who dared suggest this new leak could be the result of <em>my</em> continuous renovation activities, which is obviously untrue.</p>
<p>Because of this, the worker stormed out of the place leaving only one worker to work today.</p>
<p>To make matters worse, my uncooperative neighbour told me that she can only stay for <span class="highlight">two hours today, plus up to a maximum of 4 hours in an extra day tomorrow</span>.</p>
<p>I called the contractor and since this scenario is too complicated for his "failed PSLE" brain, so he asked <em>me</em> to calculate for him how many workers in total he needs to send on the last day (i.e. Day 4) in order to complete the job.</p>
</div>
<p>I cannot accept this. What have I done to deserve this? Failing PSLE is not an excuse for not knowing <a href="/tag/variations" rel="nofollow">proportion and variations</a> to solve my urgent problem.</p>
<p>If you can solve this, I will <i>confirm chop stamp</i> invite you to my housewarming party, where you can admire my flat, which will <i>confirm chop stamp</i> be the best of the best.</p>
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