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	<title>Comments on: Tora! Tora! Tora!</title>
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	<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora</link>
	<description>Sassy O Level Maths Tuition, Questions &#38; Tips from Singapore&#039;s Favourite Private Tutor</description>
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	<item>
		<title>By: Someone</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29051</link>
		<dc:creator>Someone</dc:creator>
		<pubDate>Tue, 25 Aug 2009 11:32:44 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29051</guid>
		<description>For some reason, when I set the graph type to line, all the intervals are equally spaced, even though the differences between them are not. It only comes out fine when I set to x y scatter. Lol.</description>
		<content:encoded><![CDATA[<p>For some reason, when I set the graph type to line, all the intervals are equally spaced, even though the differences between them are not. It only comes out fine when I set to x y scatter. Lol.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29046</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Tue, 25 Aug 2009 08:40:49 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29046</guid>
		<description>You&#039;ve committed a careless mistake when using Excel??? o.O</description>
		<content:encoded><![CDATA[<p>You've committed a careless mistake when using Excel??? o.O</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Someone</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29024</link>
		<dc:creator>Someone</dc:creator>
		<pubDate>Mon, 24 Aug 2009 15:12:31 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29024</guid>
		<description>Oh... I realize I used the wrong chart type in Excel. :$</description>
		<content:encoded><![CDATA[<p>Oh... I realize I used the wrong chart type in Excel. :$</p>
]]></content:encoded>
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	<item>
		<title>By: Someone</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29022</link>
		<dc:creator>Someone</dc:creator>
		<pubDate>Mon, 24 Aug 2009 14:51:49 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29022</guid>
		<description>I remember deriving another different equation, and the points did not lie on the line. There was a curve!</description>
		<content:encoded><![CDATA[<p>I remember deriving another different equation, and the points did not lie on the line. There was a curve!</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29020</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Mon, 24 Aug 2009 14:18:27 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-29020</guid>
		<description>It&#039;s worth noting that many &lt;em&gt;Linear Law&lt;/em&gt; questions actually specify exactly the big &lt;var&gt;Y&lt;/var&gt; and big &lt;var&gt;X&lt;/var&gt; axes you&#039;re required to plot e.g. &quot;... by plotting &lt;var&gt;y&lt;/var&gt; against &lt;var&gt;x&lt;/var&gt;&lt;sup&gt;2&lt;/sup&gt; ...&quot; to save you the trouble of having to &#039;manipulate&#039; the original non-linear equation.

But for those who don&#039;t, Miss Loi &lt;span class=&quot;fineprint&quot;&gt;(fresh from the satisfaction of seeing the car survive a week from the birds by parking at &lt;var&gt;x&lt;/var&gt; &#8776; 11.3 m)&lt;/span&gt; has adapted and compiled from an assessment book the following table of suggested &lt;var&gt;X&lt;/var&gt;s, &lt;var&gt;Y&lt;/var&gt;s, &lt;var&gt;m&lt;/var&gt; and &lt;var&gt;c&lt;/var&gt; for a range of possible equations, which she hopes will help those of you who still have trouble forming your &lt;var&gt;Y&lt;/var&gt; = &lt;var&gt;mX&lt;/var&gt;+&lt;var&gt;c&lt;/var&gt;:

&lt;div class=&quot;img-div&quot;&gt;&lt;a href=&#039;http://www.exampaper.com.sg/blog/wp-content/uploads/linear-law-notes.pdf&#039; title=&#039;Linear Law Notes&#039; rel=&quot;nofollow&quot;&gt;&lt;img src=&#039;http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-notes.gif&#039; alt=&#039;Linear Law Notes&#039; /&gt;&lt;/a&gt;&lt;div class=&quot;caption&quot;&gt;Click to view&lt;/div&gt;&lt;/div&gt;

&lt;div class=&quot;attention&quot;&gt;

&lt;img src=&quot;http://www.exampaper.com.sg/wp-content/themes/exampaper/images/attention.gif&quot; alt=&quot;Attention!&quot; /&gt; The above table is &lt;strong&gt;NOT&lt;/strong&gt; for you to memorize! Please use it more as a guide for you to practice your &#039;manipulation&#039; skills on a wide possible range of equations.

&lt;/div&gt;

To emphasize that the above table is just a guide, it should be remembered that there can be &lt;em&gt;more than one way&lt;/em&gt; to obtain your big &lt;var&gt;Y&lt;/var&gt;s and &lt;var&gt;X&lt;/var&gt;s. 

So just to illustrate this here&#039;s two more vastly-different graphs that Miss Loi has plotted for this same question, with the resultant similar estimated values for &lt;var&gt;a&lt;/var&gt; and &lt;var&gt;b&lt;/var&gt;:

&lt;ol&gt;
&lt;li&gt;

Presenting Miss Loi&#039;s graph!

&lt;m&gt;x/d = (b/a){x^2} + 5/a doubleright Y = x/d, X = x^2&lt;/m&gt;

&lt;table&gt;
&lt;tr&gt;&lt;th&gt;&lt;m&gt;x^2&lt;/m&gt;&lt;/th&gt;&lt;td&gt;25&lt;/td&gt;&lt;td&gt;100&lt;/td&gt;&lt;td&gt;225&lt;/td&gt;&lt;td&gt;400&lt;/td&gt;&lt;td&gt;625&lt;/td&gt;&lt;td&gt;900&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;th&gt;&lt;m&gt;x/d&lt;/m&gt;&lt;/th&gt;&lt;td&gt;2.000&lt;/td&gt;&lt;td&gt;11.111&lt;/td&gt;&lt;td&gt;4.673&lt;/td&gt;&lt;td&gt;7.018&lt;/td&gt;&lt;td&gt;10.000&lt;/td&gt;&lt;td&gt;13.636&lt;/td&gt;&lt;/tr&gt;
&lt;/table&gt;

&lt;a href=&#039;http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-miss-loi.gif&#039; title=&#039;Linear Law Solution (Miss Loi)&#039; rel=&quot;nofollow&quot;&gt;&lt;img src=&#039;http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-miss-loi.thumbnail.gif&#039; alt=&#039;Linear Law Solution (Miss Loi)&#039; /&gt;&lt;/a&gt;

&lt;m&gt;a approx 2.94&lt;/m&gt;
&lt;m&gt;b approx 0.039&lt;/m&gt;

&lt;/li&gt;
&lt;li&gt;

Presenting Capt Chan&#039;s graph as derived from &lt;a href=&quot;/questions/a-maths/tora-tora-tora#comment-28722&quot; rel=&quot;nofollow&quot;&gt;here&lt;/a&gt;! 

&lt;m&gt;{5d}/x = -(b)dx + a doubleright Y = 5d/x, X = dx&lt;/m&gt;

&lt;table&gt;
&lt;tr&gt;&lt;th&gt;&lt;m&gt;dx&lt;/m&gt;&lt;/th&gt;&lt;td&gt;12.5&lt;/td&gt;&lt;td&gt;9&lt;/td&gt;&lt;td&gt;48.15&lt;/td&gt;&lt;td&gt;57&lt;/td&gt;&lt;td&gt;62.5&lt;/td&gt;&lt;td&gt;66&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;th&gt;&lt;m&gt;5d/x&lt;/m&gt;&lt;/th&gt;&lt;td&gt;2.500&lt;/td&gt;&lt;td&gt;0.450&lt;/td&gt;&lt;td&gt;1.070&lt;/td&gt;&lt;td&gt;0.713&lt;/td&gt;&lt;td&gt;0.500&lt;/td&gt;&lt;td&gt;0.367&lt;/td&gt;&lt;/tr&gt;
&lt;/table&gt;

&lt;a href=&#039;http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-capt.gif&#039; title=&#039;Linear Law Solution (Capt)&#039; rel=&quot;nofollow&quot;&gt;&lt;img src=&#039;http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-capt.thumbnail.gif&#039; alt=&#039;Linear Law Solution (Capt)&#039; /&gt;&lt;/a&gt;

&lt;m&gt;a approx 3&lt;/m&gt;
&lt;m&gt;b approx 0.0399&lt;/m&gt;

&lt;div class=&quot;attention&quot;&gt;

Note that we cannot correct any possible error occurring in &lt;var&gt;d&lt;/var&gt; or &lt;var&gt;x&lt;/var&gt; in this graph. Do you know why? ;)

&lt;/div&gt;

&lt;/li&gt;
&lt;/ol&gt;

Once you&#039;ve successfully performed your &#039;manipulation&#039; (and avoid all the common careless mistakes like logarithm errors etc.), things get a little &#039;procedural&#039; (read: STRAIGHT-FORWARD) in terms of plotting the graph and solving your unknowns via &lt;var&gt;m&lt;/var&gt; and &lt;var&gt;C&lt;/var&gt; and watch your marks go &quot;1 Up&quot; ... &quot;1 Up&quot; ... &quot;1 Up&quot; like in Mario Bros so do give yourself a chance a shot at the Linear Law question in the exam even if it looks a bit daunting!
</description>
		<content:encoded><![CDATA[<p>It's worth noting that many <em>Linear Law</em> questions actually specify exactly the big <var>Y</var> and big <var>X</var> axes you're required to plot e.g. "... by plotting <var>y</var> against <var>x</var><sup>2</sup> ..." to save you the trouble of having to 'manipulate' the original non-linear equation.</p>
<p>But for those who don't, Miss Loi <span class="fineprint">(fresh from the satisfaction of seeing the car survive a week from the birds by parking at <var>x</var> &asymp; 11.3 m)</span> has adapted and compiled from an assessment book the following table of suggested <var>X</var>s, <var>Y</var>s, <var>m</var> and <var>c</var> for a range of possible equations, which she hopes will help those of you who still have trouble forming your <var>Y</var> = <var>mX</var>+<var>c</var>:</p>
<div class="img-div"><a href='http://www.exampaper.com.sg/blog/wp-content/uploads/linear-law-notes.pdf' title='Linear Law Notes' rel="nofollow"><img src='http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-notes.gif' alt='Linear Law Notes' /></a>
<div class="caption">Click to view</div>
</div>
<div class="attention">
<p><img src="http://www.exampaper.com.sg/wp-content/themes/exampaper/images/attention.gif" alt="Attention!" /> The above table is <strong>NOT</strong> for you to memorize! Please use it more as a guide for you to practice your 'manipulation' skills on a wide possible range of equations.</p>
</div>
<p>To emphasize that the above table is just a guide, it should be remembered that there can be <em>more than one way</em> to obtain your big <var>Y</var>s and <var>X</var>s. </p>
<p>So just to illustrate this here's two more vastly-different graphs that Miss Loi has plotted for this same question, with the resultant similar estimated values for <var>a</var> and <var>b</var>:</p>
<ol>
<li>
<p>Presenting Miss Loi's graph!</p>
<p><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_971_5de63931125731a97b80a233dfef6643.png" style="vertical-align:-29px; display: inline-block ;" alt="x/d = (b/a){x^2} + 5/a doubleright Y = x/d, X = x^2" title="x/d = (b/a){x^2} + 5/a doubleright Y = x/d, X = x^2"/></p>
<table>
<tr>
<th><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994_39f0ebcd1f89a04b5042e06d6be959ed.png" style="vertical-align:-6px; display: inline-block ;" alt="x^2" title="x^2"/></th>
<td>25</td>
<td>100</td>
<td>225</td>
<td>400</td>
<td>625</td>
<td>900</td>
</tr>
<tr>
<th><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_0b7499e0df5efe35535a41703da546e0.png" style="vertical-align:-14px; display: inline-block ;" alt="x/d" title="x/d"/></th>
<td>2.000</td>
<td>11.111</td>
<td>4.673</td>
<td>7.018</td>
<td>10.000</td>
<td>13.636</td>
</tr>
</table>
<p><a href='http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-miss-loi.gif' title='Linear Law Solution (Miss Loi)' rel="nofollow"><img src='http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-miss-loi.thumbnail.gif' alt='Linear Law Solution (Miss Loi)' /></a></p>
<p><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_11e11db81d4351c001c45f76839c1337.png" style="vertical-align:-5.5px; display: inline-block ;" alt="a approx 2.94" title="a approx 2.94"/><br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_bc6a982634c126ba1852e41399d82da0.png" style="vertical-align:-5.5px; display: inline-block ;" alt="b approx 0.039" title="b approx 0.039"/></p>
</li>
<li>
<p>Presenting Capt Chan's graph as derived from <a href="/questions/a-maths/tora-tora-tora#comment-28722" rel="nofollow">here</a>! </p>
<p><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_7121e5891cb6611bb9141fd5814f299c.png" style="vertical-align:-14px; display: inline-block ;" alt="{5d}/x = -(b)dx + a doubleright Y = 5d/x, X = dx" title="{5d}/x = -(b)dx + a doubleright Y = 5d/x, X = dx"/></p>
<table>
<tr>
<th><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_7258b0d64a7c5e2c15838781d34495d0.png" style="vertical-align:-5.5px; display: inline-block ;" alt="dx" title="dx"/></th>
<td>12.5</td>
<td>9</td>
<td>48.15</td>
<td>57</td>
<td>62.5</td>
<td>66</td>
</tr>
<tr>
<th><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_8692e039075f4e04fdca039cf2521d2a.png" style="vertical-align:-14px; display: inline-block ;" alt="5d/x" title="5d/x"/></th>
<td>2.500</td>
<td>0.450</td>
<td>1.070</td>
<td>0.713</td>
<td>0.500</td>
<td>0.367</td>
</tr>
</table>
<p><a href='http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-capt.gif' title='Linear Law Solution (Capt)' rel="nofollow"><img src='http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-capt.thumbnail.gif' alt='Linear Law Solution (Capt)' /></a></p>
<p><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_862e2938aad16c574fcfbd57da0652ab.png" style="vertical-align:-5.5px; display: inline-block ;" alt="a approx 3" title="a approx 3"/><br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_b8a3b3bbf70c99bd492f4c20884af6fd.png" style="vertical-align:-5.5px; display: inline-block ;" alt="b approx 0.0399" title="b approx 0.0399"/></p>
<div class="attention">
<p>Note that we cannot correct any possible error occurring in <var>d</var> or <var>x</var> in this graph. Do you know why? <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_wink.gif' alt=';)' class='wp-smiley' /> </p>
</div>
</li>
</ol>
<p>Once you've successfully performed your 'manipulation' (and avoid all the common careless mistakes like logarithm errors etc.), things get a little 'procedural' (read: STRAIGHT-FORWARD) in terms of plotting the graph and solving your unknowns via <var>m</var> and <var>C</var> and watch your marks go "1 Up" ... "1 Up" ... "1 Up" like in Mario Bros so do give yourself a chance a shot at the Linear Law question in the exam even if it looks a bit daunting!</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Someone</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28884</link>
		<dc:creator>Someone</dc:creator>
		<pubDate>Thu, 20 Aug 2009 16:57:14 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28884</guid>
		<description>[tex]d=\frac{ax}{b{x^{2}}+5}[/tex]

&lt;div class=&quot;highlight&quot;&gt;

&lt;strong&gt;Miss Loi:&lt;/strong&gt; In most Linear Law questions that come with a table of values, and with life in general, the so-called tough and critical part usually lies at the beginning - where you try every little trick you&#039;ve learnt in your &lt;a href=&quot;/tag/algebra&quot; rel=&quot;nofollow&quot;&gt;Algebra&lt;/a&gt;, &lt;a href=&quot;/tag/logarithms&quot; rel=&quot;nofollow&quot;&gt;Logarithms&lt;/a&gt;, &lt;a href=&quot;/tag/indices&quot; rel=&quot;nofollow&quot;&gt;Indices&lt;/a&gt; etc. chapters to twist and turn (like a Rubik&#039;s Cube) in order to &lt;em&gt;die die&lt;/em&gt; &lt;em&gt;manipulate&lt;/em&gt; a given grotesque equation (usually with two unknowns) into its &#039;linear&#039; form: &lt;var&gt;Y&lt;/var&gt; = &lt;var&gt;mX&lt;/var&gt; + &lt;var&gt;c&lt;/var&gt;, where &lt;var&gt;m&lt;/var&gt; and &lt;var&gt;c&lt;/var&gt; &lt;em&gt;must&lt;/em&gt; be free of all variables from the original equation.

In this example, since there isn&#039;t any unknown or variable &lt;em&gt;in the powers&lt;/em&gt; of our equation e.g. &lt;var&gt;a&lt;/var&gt;&lt;sup&gt;&lt;strong&gt;&lt;var&gt;x&lt;/var&gt;&lt;/strong&gt;&lt;/sup&gt;, &lt;var&gt;x&lt;/var&gt;&lt;sup&gt;&lt;strong&gt;&lt;var&gt;b&lt;/var&gt;&lt;/strong&gt;+1&lt;/sup&gt; etc. we can rule out the method of &#039;logging both sides&#039; and instead proceed with using algebraic manipulation (i.e. cross-multiplying) to form our &lt;var&gt;Y&lt;/var&gt; = &lt;var&gt;mX&lt;/var&gt; + &lt;var&gt;c&lt;/var&gt; expression, like what you&#039;ve done ...

&lt;/div&gt;


[tex]()\times({b{x^{2}}+5})[/tex]
[tex]d\times({b{x^{2}}+5})=ax[/tex]
[tex]db{x^{2}}+5d=ax[/tex]
[tex]\frac{()}{x^{2}}[/tex]
[tex]db+\frac{5d}{x^{2}}=\frac{a}{x}[/tex]
[tex]\frac{1}{d}\times()[/tex]
[tex]b+\frac{5}{x^{2}}=\frac{a}{dx}[/tex]
[tex]()\times\frac{1}{a}[/tex]
[tex](b+\frac{5}{x^{2}})\times\frac{1}{a}=\frac{1}{dx}[/tex]
[tex]{\frac{b}{a}}+{\frac{5}{a}}(\frac{1}{x^{2}})=\frac{1}{dx}[/tex]
[tex]\frac{1}{dx}={\frac{5}{a}}(\frac{1}{x^{2}})+{\frac{b}{a}}[/tex]

[tex]Y=mX+C[/tex]
[tex]Y=\frac{1}{dx}[/tex], [tex]m=\frac{5}{a}[/tex], [tex]X=\frac{1}{x^{2}}[/tex], [tex]C={\frac{b}{a}}[/tex]

Plot [tex]\frac{1}{dx}[/tex] against [tex]\frac{1}{x^{2}}[/tex]

&lt;div class=&quot;highlight&quot;&gt;

A little table and graph to aid the reader ;)

&lt;table&gt;
&lt;tr&gt;&lt;th&gt;&lt;m&gt;1/x^2&lt;/m&gt;&lt;/th&gt;&lt;td&gt;0.0400&lt;/td&gt;&lt;td&gt;0.0100&lt;/td&gt;&lt;td&gt;0.0044&lt;/td&gt;&lt;td&gt;0.0025&lt;/td&gt;&lt;td&gt;0.0016&lt;/td&gt;&lt;td&gt;0.0011&lt;/td&gt;&lt;/tr&gt;
&lt;tr&gt;&lt;th&gt;&lt;m&gt;1/{dx}&lt;/m&gt;&lt;/th&gt;&lt;td&gt;0.080&lt;/td&gt;&lt;td&gt;0.111&lt;/td&gt;&lt;td&gt;0.021&lt;/td&gt;&lt;td&gt;0.018&lt;/td&gt;&lt;td&gt;0.016&lt;/td&gt;&lt;td&gt;0.015&lt;/td&gt;&lt;/tr&gt;
&lt;/table&gt;

&lt;a href=&#039;http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-someone.gif&#039; title=&#039;linear-law-solution-someone.gif&#039; rel=&quot;nofollow&quot;&gt;&lt;img src=&#039;http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-someone.thumbnail.gif&#039; alt=&#039;Linear Law Solution Graph&#039; /&gt;&lt;/a&gt;

[Click Miss Loi&#039;s plotted masterpiece above to view it in its full glory]

Miss Loi&#039;s a little curious that you&#039;ve selected &lt;m&gt;1/x^2&lt;/m&gt; as your &lt;var&gt;X&lt;/var&gt;-axis since, as seen from the resultant graph, that inverse &lt;var&gt;x&lt;/var&gt;&lt;sup&gt;&lt;strong&gt;2&lt;/strong&gt;&lt;/sup&gt; term is gonna lead to pretty small values of &lt;var&gt;X&lt;/var&gt; that can be a little tricky to plot (and consequently slow you down during exam). 

But in any case, all Linear Law students will pray for that magical moment when all that manipulating is finally validated, when they look up to the skies and thank the heavens upon seeing (most of) their constellation of plotted points for &lt;var&gt;Y&lt;/var&gt; = &lt;var&gt;mX&lt;/var&gt; + &lt;var&gt;c&lt;/var&gt; align themselves on a &lt;strong&gt;straight line&lt;/strong&gt; on the graph paper.

On the other hand, this moment may serve as a wake-up call for you to urgently re-examine your &#039;manipulation&#039; workings if, to your horror, your &#039;constellation&#039; resembles some random scatter diagram or the &lt;a rel=&quot;external nofollow&quot; href=&quot;http://en.wikipedia.org/wiki/Crab_Nebula&quot; rel=&quot;nofollow&quot;&gt;Crab Nebula&lt;/a&gt;.

&lt;/div&gt;

All points other than (0.01, 0.111) lie on the line [tex]y=1.666x+0.013[/tex]

&lt;div class=&quot;highlight&quot;&gt;

So plotting &lt;m&gt;1/{dx}&lt;/m&gt; against &lt;m&gt;1/x^2&lt;/m&gt; in this example, we find that 5 of the 6 points lie along a straight line (Rejoice!), with the 6th point (corresponding to &lt;var&gt;x&lt;/var&gt;=10, &lt;var&gt;y&lt;/var&gt;=0.9) being so far off the line that it belongs to a bird that obviously can&#039;t &#039;aim&#039; well. 

In such cases, your O-Level question will usually ask something like &lt;strong&gt;&quot;It is suspected that an unusually large error occurs in one of the values of &lt;var&gt;y&lt;/var&gt;.  Identify the incorrect value and estimate its correct value.&quot;&lt;/strong&gt;

For our question, it wasn&#039;t explicitly stated if the error, if indeed there&#039;s any, occurred in &lt;var&gt;d&lt;/var&gt; or &lt;var&gt;x&lt;/var&gt; and &lt;u&gt;Miss Loi should have stated this in the question&lt;/u&gt; &lt;span class=&quot;fineprint&quot;&gt;(sorry it&#039;s really been a busy week)&lt;/span&gt; to quell any big-time controversy of whether to leave out the 6th point entirely or draw a &lt;em&gt;best-fit&lt;/em&gt; line through all 6 points. 

But since it&#039;s pretty obvious that the 5 points lie almost perfectly on a straight line, we&#039;ll choose to ignore the 6th point since its abnormally-large distance from the line will affect the accuracy of estimating &lt;var&gt;a&lt;/var&gt; and &lt;var&gt;b&lt;/var&gt; if we choose to draw a best-fit line. 

&lt;/div&gt;

[tex]\frac{5}{a}=1.666[/tex]
[tex]\frac{1}{()}[/tex]
[tex]\frac{a}{5}=\frac{1}{1.666}[/tex]
[tex]\frac{a}{5}=\frac{500}{833}[/tex]
[tex]()\times{5}[/tex]
[tex]a=\frac{500}{833}\times{5}=\frac{2500}{833}\approx{3.00}[/tex]
[tex]{\frac{b}{a}}=0.013[/tex]
[tex]()\times{a}[/tex]
[tex]b=0.013\times{a}=0.013\times{\frac{2500}{833}}=\frac{65}{1666}\approx{0.0390}[/tex]

&lt;div class=&quot;highlight&quot;&gt;

And so from your plotted graph above, we get the values of &lt;var&gt;a&lt;/var&gt; and &lt;var&gt;b&lt;/var&gt; as follows:

&lt;ul&gt;
&lt;li&gt;Gradient: &lt;m&gt;m=5/a=1.667 doubleright a approx 3&lt;/m&gt;&lt;/li&gt;
&lt;li&gt;&lt;var&gt;Y&lt;/var&gt;-intercept: &lt;m&gt;c = b/a = 0.013 doubleright b approx 0.039&lt;/m&gt;&lt;/li&gt; 
&lt;/ul&gt;

&lt;div class=&quot;attention&quot;&gt;

As an added note, Miss Loi has included within the graph some working to estimate the correct value of &lt;var&gt;d&lt;/var&gt; &lt;strong&gt;if&lt;/strong&gt; &lt;var&gt;d&lt;/var&gt; is stated in the question to be erroneous (which we now know is at &lt;var&gt;x&lt;/var&gt; = 10. 

On the other hand, would it be possible to estimate from this graph the correct value of &lt;var&gt;x&lt;/var&gt; if &lt;var&gt;x&lt;/var&gt; is stated in the question to be erroneous (assuming &lt;var&gt;d&lt;/var&gt; = 0.9 is correct)? 

&lt;/div&gt;

&lt;/div&gt;

[tex]d=\frac{ax}{b{x^{2}}+5}[/tex]
[tex]{\frac{d}{dx}}[d][/tex]

&lt;div class=&quot;highlight&quot;&gt;

Hope everyone remembers the a little &lt;em&gt;Quotient Rule&lt;/em&gt; in &lt;a href=&quot;/tag/differentiation&quot; rel=&quot;nofollow&quot;&gt;Differentiation&lt;/a&gt;: &lt;m&gt;d/{dx}(u/v) = {v{du}/{dx} - u{dv}/{dx}}/{v^2}&lt;/m&gt; used here to differentiate our original equation i.e. &lt;m&gt;d={ax}/{bx^2+5}&lt;/m&gt; (now that &lt;var&gt;a&lt;/var&gt; and &lt;var&gt;b&lt;/var&gt; are known) to obtain the value of &lt;var&gt;x&lt;/var&gt; when &lt;var&gt;d&lt;/var&gt; is at its maximum.

&lt;/div&gt;

[tex]=\frac{(b{x^{2}}+5)(a)-(ax)(2bx)}{(b{x^{2}}+5)^{2}}[/tex]
[tex]=\frac{ab{x^{2}}+5a-2ab{x^{2}}}{(b{x^{2}}+5)^{2}}[/tex]
[tex]=\frac{5a-ab{x^{2}}}{(b{x^{2}}+5)^{2}}[/tex]
[tex]{\frac{d}{dx}}[d]=0[/tex]
[tex]5a-ab{x^{2}}=0[/tex]
[tex]a(5-b{x^{2}})=0[/tex]
[tex]5-b{x^{2}}=0[/tex]
[tex]()+b{x^{2}}=0[/tex]
[tex]5=b{x^{2}}[/tex]
[tex]\frac{()}{b}[/tex]
[tex]\frac{5}{b}=x^{2}[/tex]
[tex]\sqrt{()}[/tex]
[tex]\sqrt{\frac{5}{b}}=x[/tex]
[tex]x=\sqrt{\frac{5}{b}}=\sqrt{\frac{5}{\frac{65}{1666}}}\approx{11.3205056}\approx{11.3}[/tex]

</description>
		<content:encoded><![CDATA[<p><img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_d9485a0c7f81cea585222dce7c3bc6d3.gif" class="tex" alt="d=\frac{ax}{b{x^{2}}+5}" /></p>
<div class="highlight">
<p><strong>Miss Loi:</strong> In most Linear Law questions that come with a table of values, and with life in general, the so-called tough and critical part usually lies at the beginning - where you try every little trick you've learnt in your <a href="/tag/algebra" rel="nofollow">Algebra</a>, <a href="/tag/logarithms" rel="nofollow">Logarithms</a>, <a href="/tag/indices" rel="nofollow">Indices</a> etc. chapters to twist and turn (like a Rubik's Cube) in order to <em>die die</em> <em>manipulate</em> a given grotesque equation (usually with two unknowns) into its 'linear' form: <var>Y</var> = <var>mX</var> + <var>c</var>, where <var>m</var> and <var>c</var> <em>must</em> be free of all variables from the original equation.</p>
<p>In this example, since there isn't any unknown or variable <em>in the powers</em> of our equation e.g. <var>a</var><sup><strong><var>x</var></strong></sup>, <var>x</var><sup><strong><var>b</var></strong>+1</sup> etc. we can rule out the method of 'logging both sides' and instead proceed with using algebraic manipulation (i.e. cross-multiplying) to form our <var>Y</var> = <var>mX</var> + <var>c</var> expression, like what you've done ...</p>
</div>
<p><img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_763e7f2af58c68eb9f217c408a98b1ef.gif" class="tex" alt="()\times({b{x^{2}}+5})" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_72a86d100125b50f2b51f577ad769581.gif" class="tex" alt="d\times({b{x^{2}}+5})=ax" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_e1ab19e08fd790dd36f56587dad32399.gif" class="tex" alt="db{x^{2}}+5d=ax" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_9c889a47b317e60f65944e2d111f393d.gif" class="tex" alt="\frac{()}{x^{2}}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_90141623bd642c2143a03536a3f0291c.gif" class="tex" alt="db+\frac{5d}{x^{2}}=\frac{a}{x}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_f517d0795f65a1e8c2e73c2d23f1267b.gif" class="tex" alt="\frac{1}{d}\times()" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_0dfdcf2d9d2aa0e0fc09182bec546ebb.gif" class="tex" alt="b+\frac{5}{x^{2}}=\frac{a}{dx}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_e4a3612a8fbee71c13feb47564d4757a.gif" class="tex" alt="()\times\frac{1}{a}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_46738b9bddfe31457731b05deaeb6d31.gif" class="tex" alt="(b+\frac{5}{x^{2}})\times\frac{1}{a}=\frac{1}{dx}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_f1e72dbf150c1c3a955168c06259112b.gif" class="tex" alt="{\frac{b}{a}}+{\frac{5}{a}}(\frac{1}{x^{2}})=\frac{1}{dx}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_a127675499be16faa02af64b3244ad0a.gif" class="tex" alt="\frac{1}{dx}={\frac{5}{a}}(\frac{1}{x^{2}})+{\frac{b}{a}}" /></p>
<p><img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_170a0cc12ac9b82e19faa87a998a4fe4.gif" class="tex" alt="Y=mX+C" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_af587bf271e5c274c704f8a4dfd0be36.gif" class="tex" alt="Y=\frac{1}{dx}" />, <img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_070c584505d89fd41998142f6a0929f3.gif" class="tex" alt="m=\frac{5}{a}" />, <img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_6f004ff493382cb9d5328ae5b751e93a.gif" class="tex" alt="X=\frac{1}{x^{2}}" />, <img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_c426a5b0de2be91de10ac6eea0ac3c1d.gif" class="tex" alt="C={\frac{b}{a}}" /></p>
<p>Plot <img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_8b749d2f17fb53a58b2c5a15006afb83.gif" class="tex" alt="\frac{1}{dx}" /> against <img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_54b8c3a87deab22ffa709585f2ffb861.gif" class="tex" alt="\frac{1}{x^{2}}" /></p>
<div class="highlight">
<p>A little table and graph to aid the reader <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_wink.gif' alt=';)' class='wp-smiley' /> </p>
<table>
<tr>
<th><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_f72f4ec30d901a58ad00d6962e0f220d.png" style="vertical-align:-21px; display: inline-block ;" alt="1/x^2" title="1/x^2"/></th>
<td>0.0400</td>
<td>0.0100</td>
<td>0.0044</td>
<td>0.0025</td>
<td>0.0016</td>
<td>0.0011</td>
</tr>
<tr>
<th><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_d9f4a688a8f6d696a3e1244d62363be3.png" style="vertical-align:-14px; display: inline-block ;" alt="1/{dx}" title="1/{dx}"/></th>
<td>0.080</td>
<td>0.111</td>
<td>0.021</td>
<td>0.018</td>
<td>0.016</td>
<td>0.015</td>
</tr>
</table>
<p><a href='http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-someone.gif' title='linear-law-solution-someone.gif' rel="nofollow"><img src='http://www.exampaper.com.sg/blog/wp-content/uploads/2009/08/linear-law-solution-someone.thumbnail.gif' alt='Linear Law Solution Graph' /></a></p>
<p>[Click Miss Loi's plotted masterpiece above to view it in its full glory]</p>
<p>Miss Loi's a little curious that you've selected <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_f72f4ec30d901a58ad00d6962e0f220d.png" style="vertical-align:-21px; display: inline-block ;" alt="1/x^2" title="1/x^2"/> as your <var>X</var>-axis since, as seen from the resultant graph, that inverse <var>x</var><sup><strong>2</strong></sup> term is gonna lead to pretty small values of <var>X</var> that can be a little tricky to plot (and consequently slow you down during exam). </p>
<p>But in any case, all Linear Law students will pray for that magical moment when all that manipulating is finally validated, when they look up to the skies and thank the heavens upon seeing (most of) their constellation of plotted points for <var>Y</var> = <var>mX</var> + <var>c</var> align themselves on a <strong>straight line</strong> on the graph paper.</p>
<p>On the other hand, this moment may serve as a wake-up call for you to urgently re-examine your 'manipulation' workings if, to your horror, your 'constellation' resembles some random scatter diagram or the <a rel="external nofollow" href="http://en.wikipedia.org/wiki/Crab_Nebula" rel="nofollow">Crab Nebula</a>.</p>
</div>
<p>All points other than (0.01, 0.111) lie on the line <img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_c875aea4ca0f714fdb213e935fc569e3.gif" class="tex" alt="y=1.666x+0.013" /></p>
<div class="highlight">
<p>So plotting <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_d9f4a688a8f6d696a3e1244d62363be3.png" style="vertical-align:-14px; display: inline-block ;" alt="1/{dx}" title="1/{dx}"/> against <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_f72f4ec30d901a58ad00d6962e0f220d.png" style="vertical-align:-21px; display: inline-block ;" alt="1/x^2" title="1/x^2"/> in this example, we find that 5 of the 6 points lie along a straight line (Rejoice!), with the 6th point (corresponding to <var>x</var>=10, <var>y</var>=0.9) being so far off the line that it belongs to a bird that obviously can't 'aim' well. </p>
<p>In such cases, your O-Level question will usually ask something like <strong>"It is suspected that an unusually large error occurs in one of the values of <var>y</var>.  Identify the incorrect value and estimate its correct value."</strong></p>
<p>For our question, it wasn't explicitly stated if the error, if indeed there's any, occurred in <var>d</var> or <var>x</var> and <u>Miss Loi should have stated this in the question</u> <span class="fineprint">(sorry it's really been a busy week)</span> to quell any big-time controversy of whether to leave out the 6th point entirely or draw a <em>best-fit</em> line through all 6 points. </p>
<p>But since it's pretty obvious that the 5 points lie almost perfectly on a straight line, we'll choose to ignore the 6th point since its abnormally-large distance from the line will affect the accuracy of estimating <var>a</var> and <var>b</var> if we choose to draw a best-fit line. </p>
</div>
<p><img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_368955ec5c70510c504888a282bc8957.gif" class="tex" alt="\frac{5}{a}=1.666" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_76967a21aedd13440fd5144efd92de82.gif" class="tex" alt="\frac{1}{()}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_49e9284ee83a10d2f2e4d954de84debb.gif" class="tex" alt="\frac{a}{5}=\frac{1}{1.666}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_ae72b10d6f412e24cfce62290fbd610d.gif" class="tex" alt="\frac{a}{5}=\frac{500}{833}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_0ff1554cb5cdf5e0775cceb1f27f0abb.gif" class="tex" alt="()\times{5}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_299f6dc58e780fd004c95dc657ddc626.gif" class="tex" alt="a=\frac{500}{833}\times{5}=\frac{2500}{833}\approx{3.00}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_424efa268c02fccdf7eeb4377beafa35.gif" class="tex" alt="{\frac{b}{a}}=0.013" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_b42076cdcb41dcb7f07131630e79daa0.gif" class="tex" alt="()\times{a}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_da1e86f771af9897f590739f236ce82f.gif" class="tex" alt="b=0.013\times{a}=0.013\times{\frac{2500}{833}}=\frac{65}{1666}\approx{0.0390}" /></p>
<div class="highlight">
<p>And so from your plotted graph above, we get the values of <var>a</var> and <var>b</var> as follows:</p>
<ul>
<li>Gradient: <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_947b018e253b73738aca653574961697.png" style="vertical-align:-14px; display: inline-block ;" alt="m=5/a=1.667 doubleright a approx 3" title="m=5/a=1.667 doubleright a approx 3"/></li>
<li><var>Y</var>-intercept: <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_853bbc0230dd3469848e794cc46b15e8.png" style="vertical-align:-14px; display: inline-block ;" alt="c = b/a = 0.013 doubleright b approx 0.039" title="c = b/a = 0.013 doubleright b approx 0.039"/></li>
</ul>
<div class="attention">
<p>As an added note, Miss Loi has included within the graph some working to estimate the correct value of <var>d</var> <strong>if</strong> <var>d</var> is stated in the question to be erroneous (which we now know is at <var>x</var> = 10. </p>
<p>On the other hand, would it be possible to estimate from this graph the correct value of <var>x</var> if <var>x</var> is stated in the question to be erroneous (assuming <var>d</var> = 0.9 is correct)? </p>
</div>
</div>
<p><img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_d9485a0c7f81cea585222dce7c3bc6d3.gif" class="tex" alt="d=\frac{ax}{b{x^{2}}+5}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_ec6f2a4c12a879b016b06b01ceddb259.gif" class="tex" alt="{\frac{d}{dx}}[d]" /></p>
<div class="highlight">
<p>Hope everyone remembers the a little <em>Quotient Rule</em> in <a href="/tag/differentiation" rel="nofollow">Differentiation</a>: <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_971_7e1f83e3ee8aeb350da064afc1ad006c.png" style="vertical-align:-29px; display: inline-block ;" alt="d/{dx}(u/v) = {v{du}/{dx} - u{dv}/{dx}}/{v^2}" title="d/{dx}(u/v) = {v{du}/{dx} - u{dv}/{dx}}/{v^2}"/> used here to differentiate our original equation i.e. <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_c9a59eaf3779e5f58d7755069811bdd5.png" style="vertical-align:-21px; display: inline-block ;" alt="d={ax}/{bx^2+5}" title="d={ax}/{bx^2+5}"/> (now that <var>a</var> and <var>b</var> are known) to obtain the value of <var>x</var> when <var>d</var> is at its maximum.</p>
</div>
<p><img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_c95dc347ef0894713220c852ed52f8e6.gif" class="tex" alt="=\frac{(b{x^{2}}+5)(a)-(ax)(2bx)}{(b{x^{2}}+5)^{2}}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_f8a20d91fd4b7023622665205438590d.gif" class="tex" alt="=\frac{ab{x^{2}}+5a-2ab{x^{2}}}{(b{x^{2}}+5)^{2}}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_327fbcc1f6e23a85055ec37b65d0a456.gif" class="tex" alt="=\frac{5a-ab{x^{2}}}{(b{x^{2}}+5)^{2}}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_e74b1fad944b6fe494a00f2df9e69ee5.gif" class="tex" alt="{\frac{d}{dx}}[d]=0" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_c0dcec399550f1ce492cabbc40c57726.gif" class="tex" alt="5a-ab{x^{2}}=0" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_8e44c60e59480474f04a1dfba72005b1.gif" class="tex" alt="a(5-b{x^{2}})=0" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_d869a49f9864228145d5eae4ee411d63.gif" class="tex" alt="5-b{x^{2}}=0" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_079856e4666473d464eecaac99c8beb2.gif" class="tex" alt="()+b{x^{2}}=0" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_77d4e4080e50b77f8f5236200ee34eef.gif" class="tex" alt="5=b{x^{2}}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_b0f9f716bb625d931f578251ec5d5392.gif" class="tex" alt="\frac{()}{b}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_a132107347ecd081c207159b0a765d12.gif" class="tex" alt="\frac{5}{b}=x^{2}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_1a66573c95a5b0f6f675e06df58b1de0.gif" class="tex" alt="\sqrt{()}" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_a041e2ee5b60e5afe9096301f6a49a09.gif" class="tex" alt="\sqrt{\frac{5}{b}}=x" /><br />
<img src="http://www.exampaper.com.sg/blog/wp-content/cache/tex_43ac5324970fb6d6c0ed28b7b98526ed.gif" class="tex" alt="x=\sqrt{\frac{5}{b}}=\sqrt{\frac{5}{\frac{65}{1666}}}\approx{11.3205056}\approx{11.3}" /></p>
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		<title>By: Kenny</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28777</link>
		<dc:creator>Kenny</dc:creator>
		<pubDate>Tue, 18 Aug 2009 00:46:03 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28777</guid>
		<description>Beng yeah, but supposedly damn good if you get lots of droppings on your car. Spray some water and they are off.</description>
		<content:encoded><![CDATA[<p>Beng yeah, but supposedly damn good if you get lots of droppings on your car. Spray some water and they are off.</p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28759</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Mon, 17 Aug 2009 11:54:05 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28759</guid>
		<description>Ahhh nice to see you here Captain!

Unfortunately &lt;var&gt;a&lt;/var&gt; isn&#039;t 2.1. For a start, can you list out your table of values and we&#039;ll take it from there? Miss Loi suspects that you may have been distracted while plotting your graph by a certain newbie bird that couldn&#039;t aim properly ;)


In such a typical &#039;experimental&#039; type of &lt;em&gt;Linear Law&lt;/em&gt; question that requires you to plot a graph, there can be more than one possible way to manipulate the original equation to form your &lt;var&gt;Y&lt;/var&gt; = &lt;var&gt;mX&lt;/var&gt; + &lt;var&gt;c&lt;/var&gt;, &lt;del&gt;but please &lt;strong&gt;make sure&lt;/strong&gt; that your &lt;var&gt;Y&lt;/var&gt; and &lt;var&gt;X&lt;/var&gt; contain &lt;em&gt;only&lt;/em&gt; combinations of variables &lt;var&gt;x&lt;/var&gt; and/or &lt;var&gt;y&lt;/var&gt; that are &lt;span class=&quot;highlight&quot;&gt;independent of any constant&lt;/span&gt;!&lt;/del&gt;

&lt;del&gt;*nudge nudge you to review your working above*&lt;/del&gt;

Scratch that. Following a &lt;del&gt;heated&lt;/del&gt; discussion amongst The Order of The Temple this morning, we&#039;ve concluded that &lt;var&gt;Y&lt;/var&gt; and &lt;var&gt;X&lt;/var&gt; may contain constants and coefficients (for e.g. 5&lt;var&gt;y&lt;/var&gt;) so your workings and equations are fine. 

Most likely the error arose somewhere from the way you&#039;ve plotted your values and graph. Did your table and graph tally with &lt;a href=&quot;/questions/a-maths/tora-tora-tora#comment-29020&quot; rel=&quot;nofollow&quot;&gt;the one Miss Loi plotted&lt;/a&gt; based on your equation? </description>
		<content:encoded><![CDATA[<p>Ahhh nice to see you here Captain!</p>
<p>Unfortunately <var>a</var> isn't 2.1. For a start, can you list out your table of values and we'll take it from there? Miss Loi suspects that you may have been distracted while plotting your graph by a certain newbie bird that couldn't aim properly <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_wink.gif' alt=';)' class='wp-smiley' /> </p>
<p>In such a typical 'experimental' type of <em>Linear Law</em> question that requires you to plot a graph, there can be more than one possible way to manipulate the original equation to form your <var>Y</var> = <var>mX</var> + <var>c</var>, <del>but please <strong>make sure</strong> that your <var>Y</var> and <var>X</var> contain <em>only</em> combinations of variables <var>x</var> and/or <var>y</var> that are <span class="highlight">independent of any constant</span>!</del></p>
<p><del>*nudge nudge you to review your working above*</del></p>
<p>Scratch that. Following a <del>heated</del> discussion amongst The Order of The Temple this morning, we've concluded that <var>Y</var> and <var>X</var> may contain constants and coefficients (for e.g. 5<var>y</var>) so your workings and equations are fine. </p>
<p>Most likely the error arose somewhere from the way you've plotted your values and graph. Did your table and graph tally with <a href="/questions/a-maths/tora-tora-tora#comment-29020" rel="nofollow">the one Miss Loi plotted</a> based on your equation?</p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28758</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Mon, 17 Aug 2009 11:44:27 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28758</guid>
		<description>&lt;b&gt;Kenny:&lt;/b&gt; Are you talking about those black carbon fibre stickers for the car? A bit &lt;i&gt;beng&lt;/i&gt; &lt;i&gt;leh&lt;/i&gt; ...

&lt;b&gt;mathlover:&lt;/b&gt; No time to check out the place beforehand - Miss Loi is a &lt;acronym title=&quot;Last-Minute Buddha Foot Hugging&quot;&gt;LMBFH&lt;/acronym&gt; tutor for this assignment ;)


And that UBO is actually the roof cum spoiler portion of the car, which Miss Loi thinks look more like a whaleshark now.</description>
		<content:encoded><![CDATA[<p><b>Kenny:</b> Are you talking about those black carbon fibre stickers for the car? A bit <i>beng</i> <i>leh</i> ...</p>
<p><b>mathlover:</b> No time to check out the place beforehand - Miss Loi is a <acronym title="Last-Minute Buddha Foot Hugging">LMBFH</acronym> tutor for this assignment <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_wink.gif' alt=';)' class='wp-smiley' /> </p>
<p>And that UBO is actually the roof cum spoiler portion of the car, which Miss Loi thinks look more like a whaleshark now.</p>
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		<title>By: Capt. Chan</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28722</link>
		<dc:creator>Capt. Chan</dc:creator>
		<pubDate>Sun, 16 Aug 2009 04:46:18 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/a-maths/tora-tora-tora#comment-28722</guid>
		<description>Miss Loi,
I think the equation is valid and thevalues of a is 2.1 and the b value is... erm...I am not very sureT_T.


My workings are:
[pmath]d={ax}/{bx^2+5}[/pmath]
[pmath]dbx^2+5d=ax[/pmath]
[pmath]5d=ax-dbx^2[/pmath]
[pmath]{5d}/{x}=a-dbx[/pmath]
Therefore, the gradient is -b and the Y-intercept is a. (The Linear Equation I got is Y=-bX+a, where Y is [pmath]{5d}/{x}[/pmath] and X is dx.)
Based on the graph, I think you should park at d=10.</description>
		<content:encoded><![CDATA[<p>Miss Loi,<br />
I think the equation is valid and thevalues of a is 2.1 and the b value is... erm...I am not very sureT_T.</p>
<p>My workings are:<br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_c9a59eaf3779e5f58d7755069811bdd5.png" style="vertical-align:-21px; display: inline-block ;" alt="d={ax}/{bx^2+5}" title="d={ax}/{bx^2+5}"/><br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994_0eb4ebf60697d1e45f890922004b5f8e.png" style="vertical-align:-6px; display: inline-block ;" alt="dbx^2+5d=ax" title="dbx^2+5d=ax"/><br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994_27396c2777dd02de9cfca41ef41059af.png" style="vertical-align:-6px; display: inline-block ;" alt="5d=ax-dbx^2" title="5d=ax-dbx^2"/><br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_92f054e0477a75bd5df7b96dde33e6e5.png" style="vertical-align:-14px; display: inline-block ;" alt="{5d}/{x}=a-dbx" title="{5d}/{x}=a-dbx"/><br />
Therefore, the gradient is -b and the Y-intercept is a. (The Linear Equation I got is Y=-bX+a, where Y is <img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_05ec4d236e2b62ee9a2ccffa8336cd3f.png" style="vertical-align:-14px; display: inline-block ;" alt="{5d}/{x}" title="{5d}/{x}"/> and X is dx.)<br />
Based on the graph, I think you should park at d=10.</p>
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