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	<title>Comments on: Maxima &amp; Minima &#8211; A Semi-Circular Triangular Rectangular Affair</title>
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	<description>Sassy O Level Maths Tuition, Questions &#38; Tips from Singapore&#039;s Favourite Private Tutor</description>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-1208</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Sat, 29 Sep 2007 10:03:27 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-1208</guid>
		<description>Thanks so much TYS, for pointing out this typo all the way back from the pioneering days of this blog!

At the same time, Miss Loi has taken the liberty to &#039;enhance&#039; the readability of the said working (just a little). She&#039;s feeling so noob now looking at her early posts :P</description>
		<content:encoded><![CDATA[<p>Thanks so much TYS, for pointing out this typo all the way back from the pioneering days of this blog!</p>
<p>At the same time, Miss Loi has taken the liberty to 'enhance' the readability of the said working (just a little). She's feeling so noob now looking at her early posts <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_razz.gif' alt=':P' class='wp-smiley' /> </p>
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		<title>By: TYS</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-1206</link>
		<dc:creator>TYS</dc:creator>
		<pubDate>Sat, 29 Sep 2007 09:22:16 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-1206</guid>
		<description>Anyway, I find that one of the steps in part 2 is wrong. 

GF/ AB = GD / h

instead, it should be 

GF/ AB = (h - GD)/h

Other than that, I agree with you that this is a gd qn. In fact, there are a lot of concepts tested in this qn.</description>
		<content:encoded><![CDATA[<p>Anyway, I find that one of the steps in part 2 is wrong. </p>
<p>GF/ AB = GD / h</p>
<p>instead, it should be </p>
<p>GF/ AB = (h - GD)/h</p>
<p>Other than that, I agree with you that this is a gd qn. In fact, there are a lot of concepts tested in this qn.</p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-18</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Sun, 01 Apr 2007 03:14:13 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-18</guid>
		<description>Ok answer time *drum roll*!

&lt;strong&gt;Part 1:&lt;/strong&gt;

AB = &#8730;(8&lt;sup&gt;2&lt;/sup&gt; + 6&lt;sup&gt;2&lt;/sup&gt;) = 10 cm
&#8756; Area of ABC = (1/2)(8)(6) = 24 cm&lt;sup&gt;2&lt;/sup&gt;

&lt;var&gt;h&lt;/var&gt; being height of triangle ABC, so solving this equation:
(1/2)(&lt;var&gt;h&lt;/var&gt;)(AB) = 24 cm&lt;sup&gt;2&lt;/sup&gt;

You should get &lt;var&gt;h&lt;/var&gt; = 4.8 cm! :) (shihui where u want Miss Loi to treat u???)

&lt;strong&gt;Part 2:&lt;/strong&gt;

Using similar triangles,

(GF)/(AB) = (&lt;var&gt;h&lt;/var&gt;-GD)/&lt;var&gt;h&lt;/var&gt;
GF = AB(1 - GD/&lt;var&gt;h&lt;/var&gt;)
 = (10)(1 - &lt;var&gt;x&lt;/var&gt;/&lt;var&gt;h&lt;/var&gt;)
 = 10 - 10&lt;var&gt;x&lt;/var&gt;/&lt;var&gt;h&lt;/var&gt;

Now using the value of &lt;var&gt;h&lt;/var&gt; from part 1, 10/&lt;var&gt;h&lt;/var&gt; = 10/4.8 = 25/12. 

GF = 10 - (25/12)&lt;var&gt;x&lt;/var&gt;
&#8756; &lt;var&gt;A&lt;/var&gt; = GD x GF
= &lt;var&gt;x&lt;/var&gt;( 10 - (25/12)&lt;var&gt;x&lt;/var&gt; )
= 10&lt;var&gt;x&lt;/var&gt; - (25/12)&lt;var&gt;x&lt;/var&gt;&lt;sup&gt;2&lt;/sup&gt; :)

&lt;strong&gt;Part 3:&lt;/strong&gt;

[pmath]dA/dx=10-{25/6}x=0[/pmath]
[pmath]{25/6}x=10[/pmath]
[pmath]x=2.4[/pmath]
[pmath]{d^2A}/{dx^2} = -{25/6} &lt; 0[/pmath]

&#8756; A is max when x = 2.4 cm :)

Wah type until fingers also numb liao! Actually managed to get all these maths symbols out! 

BTW thanks to all of you who tried and responded but why all only do part 1???? Next time don&#039;t 半途而废喔!</description>
		<content:encoded><![CDATA[<p>Ok answer time *drum roll*!</p>
<p><strong>Part 1:</strong></p>
<p>AB = &radic;(8<sup>2</sup> + 6<sup>2</sup>) = 10 cm<br />
&there4; Area of ABC = (1/2)(8)(6) = 24 cm<sup>2</sup></p>
<p><var>h</var> being height of triangle ABC, so solving this equation:<br />
(1/2)(<var>h</var>)(AB) = 24 cm<sup>2</sup></p>
<p>You should get <var>h</var> = 4.8 cm! <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' />  (shihui where u want Miss Loi to treat u???)</p>
<p><strong>Part 2:</strong></p>
<p>Using similar triangles,</p>
<p>(GF)/(AB) = (<var>h</var>-GD)/<var>h</var><br />
GF = AB(1 - GD/<var>h</var>)<br />
 = (10)(1 - <var>x</var>/<var>h</var>)<br />
 = 10 - 10<var>x</var>/<var>h</var></p>
<p>Now using the value of <var>h</var> from part 1, 10/<var>h</var> = 10/4.8 = 25/12. </p>
<p>GF = 10 - (25/12)<var>x</var><br />
&there4; <var>A</var> = GD x GF<br />
= <var>x</var>( 10 - (25/12)<var>x</var> )<br />
= 10<var>x</var> - (25/12)<var>x</var><sup>2</sup> <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
<p><strong>Part 3:</strong></p>
<p><img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_eee5154bfba903be0f0bfabbb869393f.png" style="vertical-align:-14px; display: inline-block ;" alt="dA/dx=10-{25/6}x=0" title="dA/dx=10-{25/6}x=0"/><br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_986_c09ab20da857ea01030666a955929229.png" style="vertical-align:-14px; display: inline-block ;" alt="{25/6}x=10" title="{25/6}x=10"/><br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_994.5_42610620edeae415874e603a7523c88e.png" style="vertical-align:-5.5px; display: inline-block ;" alt="x=2.4" title="x=2.4"/><br />
<img src="http://www.exampaper.com.sg/wp-content/plugins/wpmathpub/phpmathpublisher/img/math_979_770b10a75068bd6026d0d1239a91768c.png" style="vertical-align:-21px; display: inline-block ;" alt="{d^2A}/{dx^2} = -{25/6} < 0" title="{d^2A}/{dx^2} = -{25/6} < 0"/></p>
<p>&there4; A is max when x = 2.4 cm <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
<p>Wah type until fingers also numb liao! Actually managed to get all these maths symbols out! </p>
<p>BTW thanks to all of you who tried and responded but why all only do part 1???? Next time don't 半途而废喔!</p>
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		<title>By: shihui</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-16</link>
		<dc:creator>shihui</dc:creator>
		<pubDate>Fri, 30 Mar 2007 11:10:23 +0000</pubDate>
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		<description>haha... i got h=4.8cm, the rest dunno how to do. =P</description>
		<content:encoded><![CDATA[<p>haha... i got h=4.8cm, the rest dunno how to do. =P</p>
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		<title>By: Miss Loi</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-13</link>
		<dc:creator>Miss Loi</dc:creator>
		<pubDate>Thu, 29 Mar 2007 02:52:53 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-13</guid>
		<description>Wah Level 10 guru here to comment! *Kneels down and bow*

John: someone&#039;s trying to pwn u!

I should put the answers up soon but some of my students still haven&#039;t try yet - slackers! (Just joking here la - actually they&#039;re also very busy with school at the moment :))</description>
		<content:encoded><![CDATA[<p>Wah Level 10 guru here to comment! *Kneels down and bow*</p>
<p>John: someone's trying to pwn u!</p>
<p>I should put the answers up soon but some of my students still haven't try yet - slackers! (Just joking here la - actually they're also very busy with school at the moment <img src='http://www.exampaper.com.sg/blog/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> )</p>
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		<title>By: bruce</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-12</link>
		<dc:creator>bruce</dc:creator>
		<pubDate>Wed, 28 Mar 2007 22:31:00 +0000</pubDate>
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		<description>As a geometry teacher, I like this problem.  It touches on properties of semicircles, area of triangles, coordinate geometry, and a little derivative at the end.  Oh yes, and the height is NOT 4.25 (I don&#039;t want to spoil the answer, but it&#039;s a little taller).</description>
		<content:encoded><![CDATA[<p>As a geometry teacher, I like this problem.  It touches on properties of semicircles, area of triangles, coordinate geometry, and a little derivative at the end.  Oh yes, and the height is NOT 4.25 (I don't want to spoil the answer, but it's a little taller).</p>
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		<title>By: maple</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-11</link>
		<dc:creator>maple</dc:creator>
		<pubDate>Mon, 26 Mar 2007 14:34:12 +0000</pubDate>
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		<description>EEW! EEW! EEEEEEEWWW!!!</description>
		<content:encoded><![CDATA[<p>EEW! EEW! EEEEEEEWWW!!!</p>
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		<title>By: john</title>
		<link>http://www.exampaper.com.sg/questions/a-maths/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-10</link>
		<dc:creator>john</dc:creator>
		<pubDate>Fri, 23 Mar 2007 15:07:24 +0000</pubDate>
		<guid isPermaLink="false">http://www.exampaper.com.sg/questions/maxima-minima-a-semi-circular-triangular-rectangular-affair#comment-10</guid>
		<description>1) h=4.25
the rest dunno so difficult maybe too tired ...</description>
		<content:encoded><![CDATA[<p>1) h=4.25<br />
the rest dunno so difficult maybe too tired ...</p>
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