2012
Mon
12
Nov

GCE A Level 2012 Oct/Nov H1 Maths 8864 Paper 1 Suggested Answers & Solutions (You Are Not Forgotten)

(13)
Posted at 11:05 pm

Errr … we’ve even been pui-ed for this

Lest you feel forgotten, abandoned or unloved, let me assure the H1SD Maths Generation that you were never far from my mind while I toiled through the H2 solutions as well as my tuition classes in the past days.

Ok 废话少说, here’s the stuff you’ve been waiting for.

Click the button and grab it here!

• 1.1:

Q9(ii) – added “the advertised price decreases as the car’s age increases in a linear fashion” in response to this.
Q11(ii) – corrected the typo “insufficient evidence” to “sufficient evidence” in the concluding statement of the hypothesis test.

2012 GCE A Level H1 Maths 8864 Paper 1 suggested solutions & answers
Access it here if you’re having trouble accessing it on Facebook using your state-of-the-art smartphone

As usual, please leave a gentle comment should you spot any mistake in this set of suggested solutions.

Now to attend to the pile of comments *rubs eyes*

All the best for your remaining papers! Freedom (or the SAF) is near!

Revision Exercise

To show that you have understood what Miss Loi just taught you, you must:

1. Michelle lee says

2012
Nov
13
Tue
12:05am

1

Wah! I see my comment up there! Feeling like a celebrity LOL.

Anyway, thank you so much Mr Loi for taking painful time to upload the answers for H1 math. We really appreciate your effort :')

I'm so glad the Hypothesis testing method I did is correct! When my dad solved it, (he is a SAT math teacher) he put H1: u >300 so I thought I'd lose like 8m! Very happy now!

For qn 10, the last part, can we use bionomial distribution to solve it instead?

Thank you Mr Loi!

• 2012
Nov
17
Sat
11:12pm

1.1

Ok I'm back after a short hiatus!

For Q10(iv), yes you should get the same answer using the binomial distribution X ~ B (3, 0.62994) where the random variable X is the is the number of gardeners with > 75 plants that will flower. So,

P (X ≥ 2) = 1 − P (X ≤ 1) = ... using GC ... = 0.691

2. tere says

2012
Nov
13
Tue
12:35am

2

Hi Mr Loi!
Thank you so much for taking the time to upload this! You've no idea how much this helps *-*

I just have a question to ask for Q11)!

Why is it that it is H1 : Mean ? The questions says "at least" which would mean that the length has to be 300 or MORE. This means we are testing if the claim of the average length being MORE than 300 is correct. Hence, if it were to be rejected, the average length would be 300 or less. Is it not...?

A minor thing to note, my teachers had told me previously that it was noted in Cambridge's marking report that we ought to state the relationship for the correlation between the two variables, so for 9ii) i think we'd need to add on something like "if the age of the car increases its advertised price will drop" to get a full 2m.

That's all! Thank you so much once again! (:

• Michelle lee replied to tere’s comment

2012
Nov
13
Tue
7:55am

2.1

@tere: If we reject and conclude that the mean is 300 or less, aren't we ignoring a part of the manger's claim that the mean can be 300? So I think it is not completely accurate...?

• tere replied to Michelle lee’s comment

2012
Nov
13
Tue
11:20am

mm i think my question was a little unclear because my signs were not included.

I was confused with his answer. I didn't understand why his H1:Mean was less than 300. I had put it the same as your dad, more than.

But right now, basing on what you're saying and looking at Mr Loi's solutions again, If we're testing it to be LESS THAN 300, then it would mean that we are testing if the average length of the ball is 300 or less than 300, and in this way we can still calculate and in fact it would be more accurate! Thank you, I understand now!

• 2012
Nov
17
Sat
10:57pm

@tere: Q11(ii) is a little tricky in the sense that you are actually testing for whether the average length is less than 300 m i.e.

Ho : μ = 0
H1 : μ < 300

In this case, if Ho is rejected ⇒ average length of string is less than 300 m which counters the manager's claim of at least 300 m.

Instead, if we were to test for H1 : μ > 300, accepting or rejecting Ho wouldn't make any difference in both cases since μ will still be within "at least 300 m" territory.

Q9(ii) Hmmm I'm inclined to think that a "strong negative linear correlation" would suffice to cover the "age of car increases/price decreases part" for the (presumably) 1-mark comment since the other mark would go towards the calculation of value of the coefficient. But who am I to go against Cambridge if it's true to markers' report said this!

3. abcd says

2012
Nov
13
Tue
2:00am

3

Despite the low demand for h1's answer, i want to express my biggest thank you for taking time to come out with the answers! thank you ^^!

4. abcd says

2012
Nov
13
Tue
12:26pm

4

btw why is there a need to standardize the last qn? can't we just calculate the probability using normalcdf after obtaining the mean and variance?

• 2012
Nov
17
Sat
11:24pm

4.1

@abcd: It's perfectly fine not to standardize the normal distribution in Q12(ii). It's just a habit of mine from questions to find unknowns from given probability value(s) - which is not really necessary here

2012
Nov
13
Tue
8:47pm

5

I just wanted to check, if I left my answers for Q8 (probability) in fractions, will I be penalized?

6. Cintia says

2013
Nov
11
Mon
11:37pm

6

Hi when will the 2013 a levels h1 math answers be uploaded?! Many of my school mates said it was a harder paper as compare to last years. Is it true? Really anxoous and worried. And normally what's the marks to get an A for h1 math. Is it around the 80s? Or 90s? Cos apparently for O levels Emaths is the high 90s to score an A1. :S

One Reaction

1. Miss Loi tweeted

2012
Nov
12
Mon
3:09pm

7

#ALevel #H1 #Math suggested answers & solutions for the H1SD Math Generation: http://t.co/2t4Cx2Mz (if any of you are still around )

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