Comments on: All The Best For Your H1 / H2 Maths Papers This Week! http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week Sassy O Level Maths Tuition, Questions & Tips from Singapore's Favourite Private Tutor Sun, 05 Feb 2012 17:08:39 +0000 hourly 1 By: Mr Loi http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32227 Mr Loi Wed, 11 Nov 2009 16:23:48 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32227 Ok guys I've finally managed to get the <a href="/mr-loi-the-a-level-tutor/gce-a-level-2009-octnov-h2-maths-9740-paper-1-suggested-answers-solutions" rel="nofollow">2009 H2 Maths Paper 1 suggested solutions</a> all done up - let's all head over there! Ok guys I've finally managed to get the 2009 H2 Maths Paper 1 suggested solutions all done up - let's all head over there!

]]> By: Nash http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32222 Nash Wed, 11 Nov 2009 13:14:30 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32222 Ya ALOT of ppl from my sch dunno so im alittle reassured... For qn 2 right the summation bit I just realised i forgot to multiply by 1/2 Since A=2 and the second part was 1/(r^3-r). does that mean my whole working is wrong? i wrote the series would converge to 1/2 instead of the correct ans of 1/4 because of this >_<... Crap few more mistakes like this and i can kiss my A or B goodbye Ya ALOT of ppl from my sch dunno so im alittle reassured...
For qn 2 right the summation bit I just realised i forgot to multiply by 1/2 Since A=2 and the second part was 1/(r^3-r). does that mean my whole working is wrong? i wrote the series would converge to 1/2 instead of the correct ans of 1/4 because of this >_<...
Crap few more mistakes like this and i can kiss my A or B goodbye

]]> By: nana http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32208 nana Wed, 11 Nov 2009 07:42:11 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32208 wow wow! totally impressed by the working. really alot of people dun know?? i totally died there. wow wow! totally impressed by the working. really alot of people dun know?? i totally died there.

]]> By: kohes http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32207 kohes Wed, 11 Nov 2009 07:22:46 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32207 Oops, type too fast... The line should read: Similarly, [tex]\text{f}(3)=\text{f}(3+4)=\ldots=\text{f}(27)=2(3)-1=5[/tex]. Oops, type too fast... The line should read:

Similarly, \text{f}(3)=\text{f}(3+4)=\ldots=\text{f}(27)=2(3)-1=5.

]]> By: kohes http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32206 kohes Wed, 11 Nov 2009 07:21:05 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32206 I think you will still get some marks, it is not exactly zig-zag. The x = 0 to x = 2 part of the graph should be parabolic joining (0, 7) and (2, 3), concave downwards, while the x = 2 to x = 4 part should be a straight line joining (2, 3) and (4, 7). For (i), the question stated [tex]\text{f}(x)=\text{f}(x+4)[/tex]. In my opinion, this equation is not completely understood by many. See it as [tex]\text{f}(1)=\text{f}(1+4)[/tex], which is equal to [tex]\text{f}(5)[/tex]. This process is repeated: [tex]\text{f}(5)=\text{f}(5+4)=\text{f}(9)=[/tex]. Note that [tex]\text{f}(1)=\text{f}(5)=\text{f}(9)=\ldots=\text{f}(45)[/tex]. Therefore, we have [tex]\text{f}(1)=\text{f}(45)=7-(1)^2=6[/tex] Similarly, [tex]\text{f}(3)=\text{f}(3+4)=\ldots=\text{x}(27)=2(3)-1=5[/tex]. Well... a lot of people could not do this question, so you do not need to worry! All the best for your Paper 2 :) I think you will still get some marks, it is not exactly zig-zag. The x = 0 to x = 2 part of the graph should be parabolic joining (0, 7) and (2, 3), concave downwards, while the x = 2 to x = 4 part should be a straight line joining (2, 3) and (4, 7).

For (i), the question stated \text{f}(x)=\text{f}(x+4). In my opinion, this equation is not completely understood by many.

See it as \text{f}(1)=\text{f}(1+4), which is equal to \text{f}(5). This process is repeated:
\text{f}(5)=\text{f}(5+4)=\text{f}(9)=.

Note that \text{f}(1)=\text{f}(5)=\text{f}(9)=\ldots=\text{f}(45). Therefore, we have \text{f}(1)=\text{f}(45)=7-(1)^2=6

Similarly, \text{f}(3)=\text{f}(3+4)=\ldots=\text{x}(27)=2(3)-1=5.

Well... a lot of people could not do this question, so you do not need to worry! All the best for your Paper 2 :)

]]> By: Nash http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32203 Nash Wed, 11 Nov 2009 06:08:23 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32203 H2 paper... Aiyah totally messed up >_< oh wells... must work hard for P2, If i drew curvy line instead of zig-zag (like the cosine curve kind) should be ok right? BTW, how do u know that f(27)+f(45) gives u those 2 things? Q1)i didnt know how to do...14marks gone =_= but is it supposed to use ax^2+bx+c=10,6,5 and then solve using simultaneous eqns? H2 paper... Aiyah totally messed up >_< oh wells... must work hard for P2,
If i drew curvy line instead of zig-zag (like the cosine curve kind) should be ok right?

BTW, how do u know that f(27)+f(45) gives u those 2 things?

Q1)i didnt know how to do...14marks gone =_=
but is it supposed to use ax^2+bx+c=10,6,5 and then solve using simultaneous eqns?

]]> By: kohes http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32171 kohes Tue, 10 Nov 2009 11:29:03 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32171 Here is my working: [tex] \int_{-4}^{-2}\text{f}(x)\text{d}x=\int_{0}^{2}\text{f}(x)\text{d}x=11\frac{1}{3} [/tex] [tex] \int_{-2}^{0}\text{f}(x)\text{d}x=10 [/tex] [tex] \int_{2}^{3}\text{f}(x)\text{d}x=4 [/tex] By adding up all the areas, it will be [tex]36\frac{2}{3}[/tex]. I think Mr Loi is writing solutions now :) Here is my working:

<br /> \int_{-4}^{-2}\text{f}(x)\text{d}x=\int_{0}^{2}\text{f}(x)\text{d}x=11\frac{1}{3}<br />

<br /> \int_{-2}^{0}\text{f}(x)\text{d}x=10<br />

<br /> \int_{2}^{3}\text{f}(x)\text{d}x=4<br />

By adding up all the areas, it will be 36\frac{2}{3}.

I think Mr Loi is writing solutions now :)

]]> By: Zenology http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32169 Zenology Tue, 10 Nov 2009 11:02:22 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32169 Damn I didn't get 36 2/3. Is e answer def right? Damn I didn't get 36 2/3. Is e answer def right?

]]> By: kohes http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32168 kohes Tue, 10 Nov 2009 10:41:12 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32168 That is, if you are referring to the H2 Maths Paper. That is, if you are referring to the H2 Maths Paper.

]]> By: kohes http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32167 kohes Tue, 10 Nov 2009 10:40:47 +0000 http://www.exampaper.com.sg/mr-loi-the-a-level-tutor/all-the-best-for-your-h1-h2-maths-papers-this-week#comment-32167 Part (i): [tex]\text{f}(27) + \text{f}(45) = \text{f}(3) + \text{f}(1) = 6 + 5 = 11[/tex] Part (ii): Sketch the case when [tex]0\lt{x}\leq4[/tex]. Then just copy the graph to the left and right. You should get something zig-zag. Part (iii): [tex]36\frac{2}{3}[/tex] Part (i): \text{f}(27) + \text{f}(45) = \text{f}(3) + \text{f}(1) = 6 + 5 = 11

Part (ii): Sketch the case when 0\lt{x}\leq4. Then just copy the graph to the left and right. You should get something zig-zag.

Part (iii): 36\frac{2}{3}

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